# Top 210 Most Asked Boat and Stream Questions [ 100% FREE ]

Navigating through competitive exams requires a clear understanding of various topics, one of which is boat and stream questions. The world of boats and streams is not just about boats moving on water; it’s about understanding the intricate dance between the boat and the water’s flow. And in the realm of competitive exams, this dance translates into boat and stream questions that challenge, intrigue, and test the understanding of aspirants.

One of the primary reasons behind the popularity of boat and stream questions in Government exams is their real-world applicability. Imagine a boat navigating the waters of a stream. The way it maneuvers against or along the stream can be mathematically modeled, and this forms the basis of boat and stream questions. Given their relevance, it’s no surprise that these questions often make an appearance in the quantitative aptitude section of various exams, carrying a weightage of 1-3 marks.

But before diving headlong into boat and stream questions, it’s vital to grasp the fundamental concepts associated with boats and streams. At the heart of these questions lies the boat and stream formula. This formula, crucial for solving boat and stream questions, breaks down the dynamics of boats in different water conditions. And for those eager to delve deep into the topic, our boat and stream formula pdf offers a detailed look into the mathematical intricacies of the concept.

Understanding boats and streams is about more than just formulas; it’s about visualizing various scenarios. Consider a boat moving against the flow of water. This is termed as ‘upstream’. The speed at which the boat moves in this scenario gives us the upstream speed. On the other hand, when the boat aligns with the water’s flow, moving with the current, it’s called ‘downstream’, and we measure its net speed as the downstream speed. And of course, there are times when waters are calm, and we’re dealing with ‘still water’ scenarios, where the water speed is zero.

For many aspirants, especially those who prefer reading in Hindi, we’ve curated boat and stream questions in Hindi. This ensures that everyone, regardless of their language preference, has equal access to this crucial topic. Moreover, our boat and stream questions pdf provides a handy compilation of these questions, making it easier for aspirants to practice and master the topic.

In conclusion, boat and stream questions are not just another topic; they are a doorway to understanding the beautiful interplay between motion and resistance, between man-made vessels and nature’s flow. Whether you’re seeking the boat and stream formula or practicing with our boats and streams problems, remember that each question brings you one step closer to mastering this vital topic for your exams.

## Top 210 Most Asked Boat and Stream Questions

 71. The boat in still water travel the distance of downstream is 175% of the distance which travel upstream in the same time. If the speed of current is 4kmph, then find the speed of boat in still water?स्थिर जल में नाव द्वारा धारा के अनुकूल यात्रा, उसी समय में धारा के प्रतिकूल यात्रा करने वाली दूरी का 175% है। यदि धारा की गति 4 किमी प्रति घंटा है, तो स्थिर जल में नाव की गति ज्ञात कीजिए?A. 44/3kmphB. 46/3kmphC. 49/3kmphD. 38/3kmphE. None of these Option “A” is correct.Distance of upstream=xDistance of downstream=x*175/100=7/4xSpeed of current=4kmphSpeed of still water=y x/(y-4)=(7x/4)/y+4x(y+4)=7x/4(y-4)4y+16=7y-283y=44y=44/3 kmph 72. If the time taken by boat to travel downstream is half of the time taken by boat to travel upstream. If the boat is running in upstream and covers 120 km and also while running in downstream it covers the same distance, then what is the speed of the boat in still water?यदि नाव द्वारा धारा के अनुकूल यात्रा करने में लिया गया समय, नाव द्वारा धारा के प्रतिकूल यात्रा करने में लिए गए समय का आधा है। यदि नाव धारा के प्रतिकूल चल रही है और 120 किमी की दूरी तय करती है और धारा के अनुकूल चलते समय भी वह समान दूरी तय करती है, तो स्थिर जल में नाव की गति क्या है?A. 20 kmphB. 25 kmphC. 15 kmphD. Cannot be determinedE. None of theseOption “D” is correct.Let Speed of the boat in still water=BAnd Speed of the stream=WDownstream speed=B + WUpstream speed=B – W120/(B + W)=1/2 * (120/(B – W))2/(B + W) =1/(B – W)B + W=2B – 2WB=3WWe cannot find the answer of the question. 73. Find the time taken by a boatman to travel a distance of 270 Km downstream, where downstream speed of boatman is 300% of upstream speed of boatman, if the speed of stream is 15Kmph?एक नाविक द्वारा धारा के अनुकूल 270 किमी की दूरी तय करने में लिया गया समय ज्ञात कीजिए, जहां नाविक की धारा के अनुकूल गति नाविक की धारा के प्रतिकूल गति का 300% है, यदि धारा की गति 15 किमी प्रति घंटा है?A. 5 hoursB. 4 hoursC. 3 hoursD. 6 hours E. 8 hoursOption “D” is correct.Downstream speed/upstream speed = 3/1Downstream speed = 3xUpstream speed = xStream speed = (3x-x)/2=2x/2=xx = 15 ….givenDownstream speed = 3*15 = 45kmphTime taken = 270 / 45 = 6 hours 74. The ratio of upstream speed and downstream speed is 4: 7. If the speed of the stream is 7.5 kmph, find the average speed of still water and upstream speed.धारा के प्रतिकूल गति और धारा के अनुकूल गति का अनुपात 4:7 है। यदि धारा की गति 7.5 किमी प्रति घंटा है, स्थिर जल और धारा के प्रतिकूल गति का औसत ज्ञात कीजिए।A. 22.54 kmphB. 23.65 kmphC. 23.75 kmphD. 25.75 kmphE. 13.5 kmphOption “C” is correct.The ratio of upstream speed and downstream speed = 4: 7 (4x, 7x)Consider speed of boat = BSpeed of stream = SSpeed of boat = (4x + 7x)/2 = 5.5 xSpeed of stream = (4x – 7x)/2 = 1.5x=>7.5 = 1.5x=>x = 5Upstream speed = 4 * 5 = 20 kmphSpeed of boat = 5.5x= 5.5 * 5 = 27.5 kmphRequired average = (20 + 27.5)/2 = 23.75 kmph 75. A boat can travel 16 km downstream in 32 minutes. If the speed of the current is 1/4 of the speed of the boat in still water, what distance can the boat travel in 20 minutes?एक नाव धारा के अनुकूल 16 किमी की यात्रा 32 मिनट में कर सकती है। यदि धारा की गति स्थिर जल में नाव की गति का 1/4 है, तो नाव 20 मिनट में कितनी दूरी तय कर सकती है?A. 12 kmB. 16 kmC. 18 kmD. 8 kmE. 10 kmOption “D” is correct.Let the speed of the boat in still water be x km/hrSpeed of the current= x/4Downstream speed = x + x/4= 5x/4Downstream speed in km/hr = 16*60/28= 30 km/hrSo,5x/4= 30x = 24 km/hrDistance in 20 minutes= 24*20/60= 8 km 76. A boat travels upstream to cover 40 km and travel downstream to cover 120 km. If the ratio of the speed of boat in still water to speed of stream is 2: 1, what is the difference between the time taken by the boat covers upstream and downstream distance?एक नाव धारा के प्रतिकूल 40 किमी की दूरी तय करती है और धारा के अनुकूल 120 किमी की दूरी तय करती है। यदि स्थिर जल में नाव की गति से धारा की गति का अनुपात 2:1 है, तो नाव द्वारा धारा के प्रतिकूल और धारा के अनुकूल दूरी तय करने में लगने वाले समय में कितना अंतर है?A. 4 hoursB. 2 hoursC. 5 hoursD. Cannot be determinedE. None of theseOption “E” is correct.Speed of downstream 2x + x = 3xSpeed of upstream = 2x – x = xTime taken by the boat to cover the upstream distance = 40/xTime taken by the boat to cover the downstream distance = 120/3x = 40/xDifference = 40/x – 40/x = 0 hours 77. A boat can travel 60 km downstream in 50 min. The ratio of the speed of the boat in still water to the speed of the stream is 2: 1. How much time will the boat take to cover 80 km upstream?एक नाव धारा के अनुकूल 60 किमी की यात्रा 50 मिनट में कर सकती है। स्थिर जल में नाव की गति से धारा की गति का अनुपात 2:1 है। नाव को धारा के प्रतिकूल 80 किमी की दूरी तय करने में कितना समय लगेगा?A. 3 hours 45 minsB. 3 hours 20 minsC. 3 hours 30 minsD. 4 hours 12 minsE. None of theseOption “B” is correct.Speed of downstream = D/T = 60 / (50/60) = 60 * (60/50) = 72 km/hrThe ratio of the speed of the boat in still water to the speed of the stream= > 2: 1 (2x, x)3x = 72x = 24Speed of upstream = 2x – x = x = 24 km/hrDistance = 80 kmTime = D/S = 80/24 = 3 (8/24) hrs = 3 (1/3) hrs = 3 hours 20 mins 78. A boat covers 144 km along with stream in 6 hours and the same boat covers 216 km against stream in 18 hours. What is the distance travelled by the boat in 8 hours?एक नाव धारा के साथ 144 किमी की दूरी 6 घंटे में तय करती है और वही नाव धारा के विपरीत 216 किमी की दूरी 18 घंटे में तय करती है। 8 घंटे में नाव द्वारा तय की गई दूरी कितनी है?A. 120 kmB. 128 kmC. 136 kmD. 140 kmE. 144 kmOption “E” is correct.Speed of the boat = xSpeed of the stream = y144/(x + y) = 6x + y = 24 —–(1)216/(x – y) = 18x – y = 12 —-(2)2x = 36x = 18 kmphy = 6 kmphDistance = 18 * 8 = 144 km 79. A boat takes 39 hours for travelling downstream from point A to point B and coming back to point C midway between A and B. If the speed of the stream is 18 km/hr and the speed of the boat in still water is 32 km/hr, then find the distance between A to B?एक नाव धारा के अनुकूल बिंदु A से बिंदु B तक यात्रा करने और वापस A और B के बीच बिंदु C पर वापस आने में 39 घंटे का समय लेती है। यदि धारा की गति 18 किमी/घंटा है और स्थिर जल में नाव की गति 32 किमी/घंटा है, तो A से B के बीच की दूरी ज्ञात कीजिए?A. 600 kmB. 700 kmC. 500 kmD. 800 kmE. None of theseOption “B” is correct.Speed of downstream = 32 + 18 = 50 km/hrSpeed of upstream = 32 – 18 = 14 km/hrTotal time = 39 hoursIf distance between A to B is x, then distance between B to C = x/2,Time = Distance/Speedx / 50 + (x/2) / 14 = 39x / 50 + x / 28 = 3978x / (50 * 28) = 39x = (39 * 50 * 28) / 78 = 700 kmThe distance between A to B = 700 km 80. A man rows a boat against the stream flowing at the rate of 8 km/hr for a distance of 24 km and then turns around and rows back. If the whole trip occupies 4 hours, then find the man’s rowing speed in still water?एक आदमी 24 किमी की दूरी के लिए 8 किमी/घंटा की दर से बहने वाली धारा के प्रतिकूल, एक नाव चलाता है और फिर मुड़ता है और वापस आ जाता है। यदि पूरी यात्रा में 4 घंटे लगते हैं, तो स्थिर जल में आदमी की नौकायन गति ज्ञात कीजिये?A. 16 km/hrB. 18 km/hrC. 20 km/hrD. 22 km/hrE. None of theseOption “A” is correct.Let the speed in still water be x km/hr,Given,(24 / (x – 8)) + (24 / (x + 8)) = 424x + 192 + 24x – 192 = 4 * (x2 – 64)48x = 4x2 – 2564x2 – 48x – 256 = 0x2 – 12x – 64 = 0(x – 16) (x + 4) = 0x = 16, -4 (Negative value will be eliminated)The speed of man in still water = 16 km/hr