Set-1 Quadratic Equations (Inequalities) For SBI PO and SBI Clerk 2019 | Must Go Through These Questions

• If x > y
• If x ≥ y
• If x < y
• If x ≤ y
• If x = y or no relation can be established between ‘x’ and ‘y’.

3.

• Directions:1-5) In the following questions, two equations numbered I and II are given. You have to solve both the equations and Give Answer If

  1. x² + 25x + 156 =0
  2. y²+27y+182 =0

  • If x > y
  • If x ≥ y
  • If x < y
  • If x ≤ y
  • If x = y or no relation can be established between ‘x’ and ‘y’.
  Ans:2
  I. x² + 25x + 156 =0X² + 12x + 13x +156 =0

  (x+12) (x+13) =0

  x = -12, -13

  II. y²+27y+182 =0

  Y² + 14y + 13y + 182 =0

  (y+13) (y+14) =0

  y =-13, -14

  x ≥ y

• 2. Question

  1. 4x+2y =14
  2. 3x+6y =24

  • If x > y
  • If x ≥ y
  • If x < y
  • If x ≤ y
  • If x = y or no relation can be established between ‘x’ and ‘y’.
  Ans:3
  4x+2y =14 —– (1)
  3x+6y =24 —– (2)
  Solve the equation, we get x = 2 and y =3
  x < y

• 3. Question

  1. x = ∛1728
  2. y = √(√20736)

  • If x > y
  • If x ≥ y
  • If x < y
  • If x ≤ y
  • If x = y or no relation can be established between ‘x’ and ‘y’.
    Ans:5
  I. x = ∛1728
  x=12
  II. y = √(√20736)
  y= √144
  y = 12
  x=y

• 4. Question

  1. (x² – 12²) =0
  2. y = ∛2197

  • If x > y
  • If x ≥ y
  • If x < y
  • If x ≤ y
  • If x = y or no relation can be established between ‘x’ and ‘y’.
  Ans:3
  I. (x² – 12²) =0(x+12) (x-12) =0

  x=12, -12

  II. y = ∛2197

  y =13

  x < y

• 5. Question

  1. 4x+6y = 6
  2. 2x-3y =45

  • If x > y
  • If x ≥ y
  • If x < y
  • If x ≤ y
  • If x = y or no relation can be established between ‘x’ and ‘y’.
  Ans:1
  4x+6y = 6 —- (1)
  2x-3y =45 —- (2)
  Solve the equations, we get x = 12 and y = -7
  x> y

  Directions:6-10) In the following questions, two equations numbered I and II are given. You have to solve both questions and give answer among the following options.

  6. Question

  1. 4x²-4x-48=0
  2. 6y²-6y-12=0

  • if x>y
  • if x≥y
  • if x<y
  • if x≤y
  • if x=y or the relationship cannot be established)
  Ans:5
  I.4x²-4x-48=0
  4x²-16x+12x-48=0
  X=4,-3
  II.6y²-6y-12=0
  6y²+6y-12y-12=0
  Y=2,-1
  Thus relationship can’t be established

• 7. Question

  1. 3x²+53x+204=0
  2. 5y²+31y+48=0

  • if x>y
  • if x≥y
  • if x<y
  • if x≤y
  • if x=y or the relationship cannot be established)
  Ans:3
  I.3x²+53x+204=0
  3x²+36x+17x+204=0
  X=-17/3 , -12
  II.5y²+31y+48=0
  5y²+15y+16y+48=0
  Y=-16/5,-3
  Thus y>x

• 8. Question

  1. 2x²-39x+124=0
  2. 2y²-30y+108=0

  • if x>y
  • if x≥y
  • if x<y
  • if x≤y
  • if x=y or the relationship cannot be established)
  Ans:5
  I.2x²-39x+124=0
  2x²-8x-31x+124=0
  X=31/2, 4
  II.2y²-30y+108=0
  2y²-12y-18y+108=0
  Y=9 ,6
  Thus relationship can’t be established.

• 9. Question

  1. 8x²-18x+9=0
  2. y²+11y-432=0

  • if x>y
  • if x≥y
  • if x<y
  • if x≤y
  • if x=y or the relationship cannot be established)
  Ans:5
  I.8x²-18x+9=0
  8x²-12x-6x+9=0
  X=3/4, 3/2
  II.y²+11y-432=0
  y²+27y-16y-432=0
  y=16,-27
  Thus relationship can’t be established

• 10. Question

  1. 2x²+15x+28=0
  2. 4y²+32y+64=0

  • if x>y
  • if x≥y
  • if x<y
  • if x≤y
  • if x=y or the relationship cannot be established)
    Ans:2
  I.2x²+15x+28=0
  2x²+8x+7x+28=0
  X=-7/2 ,-4
  II.4y²+32y+64=0
  4y²+16y+16y+64=0
  Y=-4 ,-4
  Thus, X≥Y