5 Quality Data Interpretation Questions with Solutions to Improve your Score
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Study the following graph carefully and answer the given questions: The line graph shows the number of cars manufactured in six different months in two different companies
1. What is the ratio of 120% of the number of cars manufactured by company A on January and April together to the 80% of the number of cars sold by company B in march and June together?
Ans:4 Required ratio = 120/100 *(420+600):80/100*(540+320) =>6*(1020): 4*(860) =>153:86
2. Number of cars manufactured by company B on March and April together is what percentage more/less than the number of cars manufactured by company A on January and June together?
3. If the number of cars manufactured by company B on July is 120% of the average number of cars manufactured by company A for all the months together (Exclude February and march ), and then find the number of cars manufactured by B on July
Ans:2 Required number of cars = 120/100*(420+600+720+540)/4 =>6/5*2280/4=6/5*570=684
4. What is the difference between the total number of cars manufactured by company A and the total number of cars manufactured by company B?
5. In which of the following month the difference between the number of cars manufactured by company A and B is maximum?
Ans:4 January = 560-420=140 February =640-480=160 March = 540-400=140 April = 600-360=240 June= 540-320=220
Data Interpretation Questions with Solutions
Set-2 Study the following graph carefully and answer the given questions: The pie chart shows the percentage distribution of the number of bags sold by six different companies
Total difference is 32% of the total number of bags sold by all the companies together
1. Number of bags sold by company B at profit is what percentage more/less than the number of bags sold by company C at loss?
Ans:4 Total number of bags sold = 320/32*100=1000 Company A: Total bags = 1000*20/100=200 Given, Let us take bags sold at loss be x X+x+80=200 =>2x=120=>x=60 Bags sold at profit = 200-60=140 Bags sold at loss = 60 Similarly find all the bags Required percentage = (90-40)/40*100=>50/40*100 =>250/2=125%
2. What is the ratio of the number of bags sold by company A and C at profit to the number of bags sold by company D and F at loss?
Ans:3 Total number of bags sold = 320/32*100=1000 Company A: Total bags = 1000*20/100=200 Given, Let us take bags sold at loss be x X+x+80=200 =>2x=120=>x=60 Bags sold at profit = 200-60=140 Bags sold at loss = 60 Similarly find all the bags Required ratio = (140+60): (75+25)=200:100=2:1
3. What is the average number of bags sold by all the companies at profit?
Ans:1 Total number of bags sold = 320/32*100=1000 Company A: Total bags = 1000*20/100=200 Given, Let us take bags sold at loss be x X+x+80=200 =>2x=120=>x=60 Bags sold at profit = 200-60=140 Bags sold at loss = 60 Similarly find all the bags Required average = (140+90+60+175+120+75)/6 =>660/6=110
4. In which company the number of bags sold at loss is maximum?
Ans:5 Total number of bags sold = 320/32*100=1000 Company A: Total bags = 1000*20/100=200 Given, Let us take bags sold at loss be x X+x+80=200 =>2x=120=>x=60 Bags sold at profit = 200-60=140 Bags sold at loss = 60 Similarly find all the bags From the table company E sold maximum number of bags at loss
5. Which company sold the bags closest to the average number of bags sold by all the companies together?
Ans:2 Total number of bags sold = 320/32*100=1000 Company A: Total bags = 1000*20/100=200 Given, Let us take bags sold at loss be x X+x+80=200 =>2x=120=>x=60 Bags sold at profit = 200-60=140 Bags sold at loss = 60 Similarly find all the bags Average number of bags sold by all the companies = 1000/6= 166.67 Company B sold near to the average number of bags sold by all the companies
Data Interpretation Questions with Solutions
Set-3
Study the following graph carefully and answer the given questions The following table shows the number of students participated in Volley ball, cricket and other games in five different schools 1. What is the difference between the total number of students participated in volley ball from school A and D and the total number of students participated in cricket from school B and C?
2. Find the total number of students participated in other games from all the schools
Ans:3 Required total = 252+288+320+288+240=1388
3. If a total student in school F is 20% more than the total number of students participated in cricket from schools E and C together, and then find the total students in school F
Ans:2 Total students in school F = (180+200)*120/100=456
4. What is the difference between the total number of students participated in volley ball and the total number of students participated in Cricket?
5. In which school has maximum students participated in other games?
Ans:4
Data Interpretation Questions with Solutions
Set-4 Study the following graph carefully and answer the given questions The pie chart shows the percentage distribution of number of students applied for two competitive exams (IBPS PO and SBI PO) in different years
1. Find the total number of students applied SBI PO exams in 2012 and 2016 together, if the total number of students applied in the year 2014 is 4500
Ans:3 Required total = 4500/15*100*(20/100*60/100+25/100*40/100) =>30000*1/5*(3/5+2/4) =>6000*(12+10)/20 =>6600
2. What is the ratio of the number of students applied IBPS PO exam in 2013 and 2015 together to the total number of students applied SBI PO exam in same years?
Ans:4 Required ratio = (25/100*25/100*x+30/100*15/100*x) : (75/100*25/100*x+70/100*15/100*x) = 0.1075 x : 0.2925x = 43: 117
3. What is the difference between the total number of students applied IBPS PO in the year 2013, 2014 and 2015 and the total number of students applied SBI PO in the same years, if the total number of students applied in the year 2012 is 4000?
Ans:1 Total students = 4000/20*100=20000 Required difference = 20000*{25/100*50/100+15/100*40/100}=20000*(1/8+3/50) =>20000*37/200=3700
4. Number of students applied for SBI PO exam in 2016 is what percentage more/less than the number of students applied for IBPS PO exam in 2014?
Set-5 Refer to the table and answer the following questions: 1. If the number of male post graduate employees in company H is 1800, what percent of the female employees in that particular company are post graduate?
Ans:1 Number of Post graduate employees in Company H = 3360 *(80/100) = 2688 Number of female post graduate employees in Company H = 2688 – 1800 = 888 Required Percentage = (888 * 100)/1200 = 74%
2. In which of the given companies is the percentage of women employees with respect to the total number of employees (both males and females) in that company the second lowest?
Ans:4 Company A : (7/12 )*100 = 58.33% Company B : (5/16 )*100 = 31.25% Company C : (11/21)*100 = 52.38% Company D : (2/5)*100 = 40% Company E : (6/13)*100 = 46.15% Company F : (21/41)*100 = 51.21% Company G : (7/15)*100 = 46.66% Company H : (5/14)*100 = 35.71%
3. What is the ratio of the total number of male employees in companies B and H together to the total number of female employees in Companies C and D together?
4. What is the difference between the average number of post graduate employees in companies A, B and D together and the average number of post graduate employees in companies F, G and H?
Ans:3 Average number of post graduate employees in companies A, B and D = (1926 + 1872 + 2145)/3 = 5943/3 = 1981 Average number of post graduate employees in companies F, G and H = (2091 + 2046 + 2688)/3 = 6875/3 = 2275 Difference = 2275 – 1981 = 294
5. Which of the given companies has the highest number of average employees per office?
Ans:4 Company A – 2568/16 = 160.5 ; Company B – 2880/18 = 160 Company C – 2310/14 = 165 ; Company D – 3575/22 = 162.5 Company E – 2054/13 = 158 ; Company F – 2788/17 = 164 Company G – 3720/24 = 155 ; Company H – 3360/21 = 160
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