Top180 Mixture And Alligation Questions For 100% Free [Effective]

Navigating the world of competitive exams, a consistent topic that emerges is Mixture and Alligation Questions. It’s hard to miss how these questions feature prominently in the quantitative aptitude sections of numerous Government exams. As you prepare for these tests, you’ll find that understanding Mixture and Alligation Questions is essential for success.

Most candidates preparing for upcoming Government exams often find the section on Mixture and Alligation Questions a tad challenging. While the range is typically 1-3 questions from this topic, they can be slightly tricky to decipher. This makes practicing Mixture and Alligation Questions crucial for those aiming for a high score.

But what exactly are these questions about? Let’s break it down. The concept is rooted in mixtures and alligations. When we talk about a mixture, we refer to the blending of two or more entities. The term alligation, on the other hand, helps us determine the ratio in which these ingredients or items are combined. To succeed in Mixture and Alligation Questions, an understanding of the mixture and alligation formula and the mixture and alligation replacement formula is vital. Moreover, being familiar with the alligation and mixture formula can make the problem-solving process smoother.

For our Hindi-speaking aspirants, this topic is equally critical. Understanding mixture and alligation in hindi or the mixture and alligation meaning in hindi can be advantageous. By doing so, they can better tackle Mixture and Alligation Questions in a language they’re more comfortable with.

In this article, our aim is clear. We want to provide you with a comprehensive understanding of Mixture and Alligation Questions. By delving deep into the concept, important formulas like the mixture and alligation formula, and various problems associated with the topic, we hope to arm you with the knowledge and skills to tackle even the most challenging mixture and alligation problems. Specifically, for those aiming to crack bank exams, focusing on mixture and alligation questions for bank is paramount.

Considering the sectional cut-offs in almost all competitive exams, equal attention must be given to each subject. This is why emphasis on Mixture and Alligation Questions cannot be understated.

Top180 Mixture And Alligation Questions :

31. The cost of rice A is Rs. 24 per kg and the cost of rice B is Rs. x. 30 kg of rice A and 20 kg of rice B was mixed and sold at a profit of 50% at a rate of Rs. 43.2 per kg. Find the value of x.

चावल A का क्रय मूल्य 24 रुपये प्रति किलोग्राम है और चावल B का क्रय मूल्य x रुपये है। 30 किलो चावल A और 20 किलो चावल B को आपस में मिलाया जाता हैं और इसको 50% के लाभ पर 43.2 रुपये प्रति किलोग्राम की दर से बेचा जाता है। x का मान ज्ञात कीजिए?

Option “C” is correct.

∵ The selling price of rice = Rs. 43.2 per kg

∴ The cost price of rice = 43.2 × 100/150 = Rs. 28.8 per kg

⇒ The cost price of 50 kg = 28.8 × 50 = Rs. 1440

According to question

⇒ 24 × 30 + 20 × x = 1440

⇒ x = Rs. 36

32. In what ratio should cement costing Rs. 250 per bag be mixed with cement costing Rs. 325 per bag so that the cost of the mixture is Rs. 300 per bag. (A bag of cement is 50 kg).

250 रुपये प्रति बैग वाली सीमेंट को, 325 रुपये प्रति बैग वाली सीमेंट के साथ किस अनुपात में मिलाया जाए कि मिश्रण की लागत 300 रुपये प्रति बैग आए (सीमेंट का एक बैग 50 किग्रा का है)।

Option “A” is correct.

Let the number of bags be x costing per bag Rs 250 

Let the number of bags be y costing per bag Rs 325

Total cost of x bags = x × 250 = 250x 

Total cost of y bags = y × 325 = 325y 

According to the question 

(250x + 325y)/(x + y) = 300 

⇒ x/y = 1/2 

∴ ratio of bag costing 250 to the bag cost 325 is 1 : 2

33. The ratios of acid and water in vessels A and B are 4 : 5 and 7 : 5, respectively. In what ratio should the contents of A and B be mixed to get a solution containing 50% acid?

पात्र A और B में एसिड और पानी का अनुपात क्रमशः 4 : 5 और 7 : 5 है। 50% एसिड युक्त विलयन प्राप्त करने के लिए A और B की सामग्री को किस अनुपात में मिश्रित किया जाना चाहिए?

Option “C” is correct.

The ratio of acid to water in vessel A is 4 : 5 

Let the total volume of acid and water be 4x and 5x 

The ratio of acid to water in vessel B is 7 : 5 

Let the total volume of acid and water be 7y and 5y

According to the question volume of water and acid must be equal 

So,

(4x + 7y) : (5x + 5y) = 1 : 1 

⇒ x = 2y 

Putv value of x = 2y to get volume 

Volume of vessel A = 4x + 5x = 9x 

⇒ 18y 

Volume of vessel B = 7y + 5y 

⇒ 12y 

Ratio of vessel A to B 

Volume of vessel A : Volume of vessel B = 18y : 12y 

⇒ 3 : 2 

∴ 3 : 2 will be the ratio at which vessel A and B must be mixed

34. A vendor bought two varieties of tea, brand A and brand B, costing Rs. 15 per 100 g and Rs. 18 per 100 g, respectively, and mixed them in a certain ratio. Then, he sold the mixture at Rs. 20 per 100 g, making a profit of 20%. What was the ratio of brand A to brand B tea in the mixture?

एक विक्रेता ने दो प्रकार की चाय ब्रांड A और ब्रांड B को खरीदा, जिसका क्रय मूल्य क्रमशः 15 रुपये प्रति 100 ग्राम और 18 रुपये प्रति 100 ग्राम हैं, और उन्हें एक निश्चित अनुपात में मिलाया। उन्होंने इस मिश्रण को 20 रुपये प्रति 100 ग्राम बेचकर 20% का लाभ कमाया। मिश्रण में ब्रांड A से ब्रांड B चाय का अनुपात क्या था?

Option “A” is correct.

Let x gram of brand A and y gram of brand B is mixed.

For 100g brand A costs Rs. 15

For x g brand A will cost 15x/100

For 100g brand B costs Rs. 18

For y g brand B will cost 18x/100

So, the total cost price for (x + y) grams is

⇒ x + y = 15x/100 + 18y/100      —-(i)

Sold at Rs. 20 with 120% profit, Cost price will be

⇒ 100% = (20/120) × 100 = Rs. 100/6

Cost price for 100g is Rs. 100/6,

Now find cost price for (x + y) grams

⇒ x + y = (100/6) × {(x + y)/100}

⇒ x + y = (x + y)/6

Put value of equation(i)

⇒ 15x/100 + 18y/100 = (x + y)/6

⇒ 90x + 108y = 100x + 100y

⇒ 8y  = 10x

⇒ x/y = 8/10 = 4/5

∴ The ratio of the mixture of Brand A and B is 4 : 5

35. A solution of milk and water contains milk and water in the ratio of 3 : 2. Another solution of milk and water contains milk and water in the ratio of 2 : 1. Forty litres of the first solution is mixed with 30 litre of the second solution. The ratio of milk and water in the resultant solution is:

दूध और पानी के एक मिश्रण में दूध और पानी 3 : 2 के अनुपात में है। दूध और पानी के एक और मिश्रण में दूध और पानी 2 : 1 के अनुपात में है। पहले मिश्रण के चालीस लीटर को दूसरे मिश्रण के 30 लीटर के साथ मिश्रित किया जाता है। परिणामी मिश्रण में दूध और पानी का अनुपात है:

Option “A” is correct.

Volume of milk in first solution = (3/5) × 40 liters

⇒ 24 liters

Volume of water in first solution = (2/5) × 40 liters

⇒ 16 liters

Volume of milk in second solution = (2/3) × 30 liters

⇒ 20 liters

Volume of water in second solution = (1/3) × 30 liters

⇒ 10 liters

Volume of milk in new mixture = Volume of milk in first solution + Volume of milk in second solution

⇒ (24 + 20) liters

⇒ 44 liters

Volume of water in new mixture = Volume of water in first solution + Volume of water in second solution

⇒ (16 + 10) liters

⇒ 26 liters

Ratio of milk and water in mixture = 44/26

⇒ 22/13

⇒ 22 : 13

∴ The ratio of milk and water in the resultant solution is 22 : 13 

36. A container contains 20 L mixture in which there is 10% sulphuric acid. Find the quantity of sulphuric acid to be added in it to make the solution to contain 25% sulphuric acid.

एक पात्र में 20 लीटर का मिश्रण है जिसमें 10% सल्फ्यूरिक अम्ल है। ज्ञात कीजिए कि सल्फ्यूरिक अम्ल की कितन मात्रा जोड़ने पर मिश्रण को 25% सल्फ्यूरिक अम्ल युक्त घोल बनाया जा सकता है।

Option “B” is correct.

According to the question 

The quantity of Sulphuric acid in the mixture is 

⇒ 20 × 10%

⇒ 2 L 

The remaining quantity in the mixture is 

⇒ 20 – 2

⇒ 18 L

After, adding Sulphuric acid to the mixture, the remaining quantity becomes 75% of the mixture, then 

The whole quantity of the mixture is 

⇒ 18 × 100/75

⇒ 24 L 

Now, 

In the mixture, the quantity of Sulphuric acid is 

⇒ 24 × 25%

⇒ 6 L

The quantity of Sulphuric acid added to the mixture is 

⇒ 6 – 2

⇒ 4 L

∴ The quantity of Sulphuric acid is added to the mixture is 4 L. 

37.In what ratio should sugar costing Rs. 40 per kg be mixed with sugar costing Rs. 48 per kg , so as to earn a profit of 20% by selling the mixture at Rs. 54 per kg?

किस अनुपात में चीनी को 40 रुपये प्रति किलोग्राम और चीनी को 48 रुपये प्रति किलोग्राम के हिसाब से मिलाया जाना चाहिए, ताकि मिश्रण को 54 रुपये प्रति किलोग्राम के हिसाब से बेचकर 20% का मुनाफा कमाया जा सके?

Option “C” is correct.

Let the cost price of whole mixture be Rs. x.

⇒ x = 54 × 100/120

⇒ x =  Rs. 45 

Ratio = (48 – 45) ∶ (45 – 40)

⇒ 3 ∶ 5

∴ The ratio is 3 : 5.

38. In a mixture of 60 litres, milk and water are in the ratio 2 : 1. Find the quantity of water to be added to make the ratio 4 : 3

60 लीटर के मिश्रण में, दूध और पानी 2 : 1 के अनुपात में हैं। 4 : 3 का अनुपात बनाने के लिए मिलाए जाने वाले पानी की मात्रा ज्ञात कीजिये।

Option “B” is correct.

⇒ In the Mixture of 60 liter = milk + water = 2 + 1 unit = 3 unit

⇒ 3 unit = 60 liter

⇒ 1 unit = 20 liter

⇒ Milk: Water = 2 × 20: 1 × 20 = 40 : 20

Now as given to make the ratio of Milk: Water = 4 : 3 by adding X liter of water

⇒ 40/(20 + X ) = 4/3

⇒ 40 × 3 = 4 × ( 20 + X )

⇒ 120 = 80 + 4X

⇒ 4X = 40

∴ X = 10

39. Two alloys A and B contain copper and zinc in the ratio 7 : 2 and 5 : 3 respectively. How many kg of A and B must be melted in order to get an alloy of 44 kg containing copper and Zinc in the ratio 3 : 1?

दो मिश्रधातु A और B में क्रमशः 7 : 2 और 5 : 3 के अनुपात में तांबा और जस्ता है। 3 : 1 के अनुपात में तांबा और जस्ता युक्त 44 किलोग्राम मिश्रधातु प्राप्त करने के लिए A और B की कितनी किलोग्राम मात्रा को पिघलाया जाना चाहिए?

Option “D” is correct.

Let x liters is added from alloy A and y liters is added from alloy B.

Then (7x/9) + (5y/8) / (2x/9) + (3y/8) = 3 / 1

⇒ (7x/9) + (5y/8) = (6x/9) + (9y/8)

⇒ [(7x-6x)/9] = [(9y-5y)/8]

⇒ (x/9) = (4y/8)

⇒ (x/y) = (9/2)

⇒ x : y = 9 : 2

Quantity taken from alloy A = (44/11) × 9

⇒ 4 × 9

⇒ 36 kg

Quantity taken from alloy B = (44/11) × 2

⇒ 4 × 2

⇒ 8 kg

∴ 36 kg added from alloy A and 8 kg added from alloy B

40. An alloy X contains by weight copper and tin in the ration 7 : 3 and alloy Y contain copper and tin in the ratio 3 : 2. X and Y are taken in the ratio 4 : 1 and melted to form alloy Z. The percentage of copper in alloy Z is:

एक मिश्रधातु X में भार के अनुसार तांबे और टिन का अनुपात 7 : 3 है और मिश्रधातु Y में तांबे और टिन का अनुपात 3 : 2 है। X और Y को 4 : 1 के अनुपात में लिया जाता है और मिश्रधातु Z बनाने के लिए पिघलाया जाता है। मिश्रधातु Z में तांबे का प्रतिशत है:

Option “D” is correct.

Quantity of copper in 10units of X = 7units

Similarly, Quantity of copper in 10units of Y = 6units

To form Z, we need X : Y = 4 : 1

∴ 40units of X contains 28 units copper and 10units of Y contains 6units copper

∴ in total 50units, copper is 34units required % = (34/50) × 100 = 68%

∴ the required percentage = 68%