Top 270+ Problems on Ages Questions for 100 % Free

Understanding problems on ages questions is pivotal for aspirants looking to crack competitive exams. A frequently addressed topic in the quantitative aptitude section, problems on ages questions is a familiar sight in many government exams. At first glance, these aptitude problems on ages might seem daunting. Yet, with a solid grasp of the underlying concepts, cracking aptitude problems on ages becomes much simpler. Interestingly, many candidates have come across problems on ages questions and answers as they prepare, underscoring the theme’s importance.

Problems on ages questions may initially read as complicated brain teasers. However, diving deep, one realizes they’re often straightforward. What’s fascinating is how these problems on ages for bank exams and other competitive tests range from direct questions to equation forms. And, there’s more than just the basic questions. Problems on ages questions and answers can also be integral to sections like data sufficiency or data interpretation. Thus, understanding aptitude problems on ages is absolutely crucial.

If you’ve ever come across problems on ages for bank exams or other competitive tests like SSC, SBI, RBI, or even state government exams, you’d know how often they feature. While problems on ages questions is a broad category, a predominant portion of them leans on the concept of ratio. Get the ratio right, and most of your aptitude problems on ages become easy to tackle.

So, for all those gearing up for exams and delving into problems on ages questions and answers, remember, it’s all about understanding the basics. And once you do, not just problems on ages for bank exams, but for all competitive exams, will be within your grasp.

270+ Problems on Ages Questions

151. Ratio of the ages of Shon and Sania before 6 years is 4:5 and the ratio of the age of Shon to Sania after 12 years will be 7:8. What is the ratio of the present age of Shon to Sania?

6 वर्ष पहले शॉन और सानिया की आयु का अनुपात 4: 5 है और 12 वर्ष के बाद शॉन और सानिया की आयु का अनुपात 7: 8 होगा। शॉन और सानिया की वर्तमान आयु का अनुपात क्या है?

A. 5:6
B. 6:7
C. 7:8
D. 4:5
E. None of these

Option “A” is correct.

(4x + 6 + 12)/(5x + 6 + 12) = 7/8

(4x + 18) * 8 = (5x + 18) * 7

32x + 144 = 35x + 126

3x = 18

x = 6 years

Preset age ratio of Shon to Sania= (4 * 6 + 6):(5 * 6 + 6)

= 30:36

=5:6

152. Average age of A, B and C is 48 years. Ratio of the ages of A and B is 10: 11 and the ratio of the ages of A and C 2: 3. What is C’s age before 15 years?

A, B और C की औसत आयु 48 वर्ष है। A और B की आयु का अनुपात 10: 11 है और A और C की आयु का अनुपात 2:3 है। C की आयु 15 वर्ष से पहले क्या था?

A. 40 years
B. 45 years
C. 50 years
D. 55 years
E. None of these

Option “B” is correct.

A: B: C = 10: 11: 15

A + B + C = 48 * 3 = 144

C’s present age = 15/36 * 144 = 60 years

C’s age 15 years before = 60 – 15 = 45 years

153. The ratio of ages of A, before 4 years and B, after 4 years is 5: 9. If the difference between their ages is 4, then find the average age of them.

4 वर्ष से पहले A और 4 वर्ष के बाद B की आयु का अनुपात 5: 9 है। यदि उनकी आयु का अंतर 4 है, फिर उनका औसत आयु ज्ञात करें।

A. 23 years
B. 22 years
C. 21 years
D. 24 years
E. 25 years

Option “C” is correct.

Given that,

9x – 4 – (5x + 4) = 4

4x = 12

x = 3

The age of A = 5 * 3 + 4 = 19

The age of B = 9 * 3 – 4 = 23

Required average = (19 + 23)/2 = 21 years

154. Ratio of ages of Q to P is 5 : 4 and the ratio of ages of R to Q is 5 : 6. If the average of their ages is 79 years. Then find the ratio of the 8 years before the age of P to 10 years before the age of Q?

Q से P की आयु का अनुपात 5:4 है और R से Q की आयु का अनुपात 5:6 है। यदि उनकी आयु का औसत 79 वर्ष है। तो P की आयु से 8 वर्ष पहले और Q की आयु से 10 वर्ष पहले का अनुपात ज्ञात कीजिए?

A. 3 : 5
B. 4 : 9
C. 8 : 3
D. 5 : 7
E. None of these

Option “E” is correct.

Ratio of age of P and Q is 4 : 5.

And the ratio of age of Q and R = 6 : 5

So, ratio of P : Q : R = (4 × 6) : (5 × 6) : (5 × 5)

= 24 : 30 : 25

Then, according to the question,

24x + 30x + 25x = 3 × 79

79x = 3 × 79

x = 3 × 79/79

x = 3

So, the age of P, Q and R = 72 years, 90 years and 75 years.

Thus, the ratio of age is = (72 – 8) : (90 – 10)

= 64 : 80 => 4 : 5

155. Ratio of the ages of A and B is 3:5 and after 10 years, B’s age is double of C’s age. If C’s 16th birthday is celebrated in 4 years before, then find the present age of A.

A और B की आयु का अनुपात 3: 5 है और 10 वर्ष के बाद, B की आयु C की आयु की दोगुनी है। यदि C का 16 वां जन्मदिन 4 वर्ष पहले मनाया गया है, तो A की वर्तमान आयु को ज्ञात कीजिए।

A. 45 years
B. 30 years
C. 27 years
D. 48 years
E. None of these

Option “B” is correct.

C’s present age = 20 years

B’s present age + 10 = (20 + 10) * 2

B’s present age = 50

A’s present age = 3/5 * 50 = 30 years

156. The present age of Shivani is 1/3rd of her mother’s age, after 5 years mother’s age will be twice the age of her son, her son celebrated 10th birthday 7 years before then find the age of shivani after 5 years.

शिवानी की वर्तमान आयु उसकी माँ की आयु की 1 / 3 वां है, 5 वर्ष के बाद माँ की आयु उसके पुत्र से दोगुनी होगी, उसके पुत्र ने 7 वर्ष पहले 10 वां जन्मदिन मनाया था और फिर 5 वर्ष के बाद शिवानी की आयु ज्ञात क्या होगी।

A. 13 years
B. 18 years
C. 15 years
D. 17 years
E. 20 years

Option “B” is correct.

Let present age of mother = 3x, therefore present age of shivani =x

Her son celebrated 10th birthday 7 years before, therefore present age of her son =17 years

Mother’s age after 5 years

3x+5 = 2(17+5)

3x+5= 44

x=13

Present age of mother =39

Present age of Shivani = 13

Age of Shivani after 5 years = 13+5 =18 years

157. Aria’s age before five years and Ruby’s age after 3 years is in the ratio of 5:4 and the ratio of Ruby’s age one year ago and Aria’s age one year ago is 5:7, then what is the Ruby’s age before 11 years?

पांच वर्ष पहले आरिया की आयु और 3 वर्ष बाद रूबी की आयु का अनुपात 5:4 है और एक वर्ष पहले रूबी की आयु और एक वर्ष पहले आरिया की आयु का अनुपात 5:7 है, तो 11 वर्ष पहले रूबी की आयु कितनी है?

A. 41 years
B. 61 years
C. 50 years
D. 30 years
E. 55 years

Option “C” is correct.

Let the present age of Aria and Ruby are x and y years respectively.

(x – 5)/(y + 3) = 5/4

4x – 5y = 35 ——–(1)

(x – 1)/(y – 1) = 7/5

7y – 5x = 2 ———-(2)

From (1) and (2),

y = 61 years

Ruby’s age before 11 years = 61 – 11 = 50 years

158. The present age of L is 4 years more than the present age of M and ratio of age of L before 5 years to the age of M after 4 years is 4:5. Find the sum of the age of L after 5 years and age of M after 9 years.

L की वर्तमान आयु M की वर्तमान आयु से 4 वर्ष अधिक है और 5 वर्ष पहले L की आयु से 4 वर्ष बाद M की आयु का अनुपात 4:5 है। 5 वर्ष बाद L की आयु और 9 वर्ष बाद M की आयु का योग ज्ञात कीजिए।

A. 45 years
B. 35 years
C. 60 years
D. 72 years
E. None of these

Option “C” is correct.

Present age of L = 4x + 5

Present age of M = 5x – 4

(4x + 5) – (5x – 4) = 4

-x + 9 = 4

x = 9 – 4 = 5

Present age of L = 4 * 5 + 5 = 25 years

Present age of M = 5 * 5 – 4 = 21 years

Required sum = (25 + 5) + (21 + 9) = 30 + 30 = 60 years

159. 12 years ago A’s age is equal to the B’s age after 10 years. If after 16 years, the ratio of the ages of A and B is 5:3, what is B’s age after 10 years?

12 वर्ष पहले A की आयु 10 वर्ष के बाद B की आयु के बराबर होती है। यदि 16 वर्ष के बाद A और B की आयु का अनुपात 5: 3 है, तो 10 वर्ष के बाद B की आयु क्या है?

A. 22 years
B. 33 years
C. 18 years
D. 27 years
E. None of these

Option “D” is correct.

A – 12 = B + 10

A – B = 22

5x – 3x = 22

2x = 22

x = 11

B’s age = 11 * 3 = 33 years

B’s present age = 33 – 16 = 17

After 10 years B’s present age = 10 + 17 = 27 years

160. A is 8 years older than B and B is 12 years younger than C. If the sum of the ages of A, B and C is 80 years, then what is B’s age after 10 years?

A, B से 8 वर्ष बड़ा है और B,C से 12 वर्ष छोटा है। यदी A, B और C की आयु का योग 80 वर्ष है, तो 10 वर्ष के बाद B की आयु क्या है?

A. 20 years
B. 30 years
C. 28 years
D. 22 years
E. None of these

Option “B” is correct.

A – B = 8

C – B = 12

A + B + C = 80

B + 8 + B + 12 + B = 80

3B = 60

B = 20 years

After 10 years B’s age = 20 + 10 = 30 years