260+ Most Asked Ratio And Proportion Questions [100% Free ]

Navigating the landscape of mathematics, one often comes across the fundamental concepts of “ratio and proportion questions“. Grasping the understanding of these is crucial, as ratio and proportion are woven deeply into the fabric of our daily activities, from intricate business dealings to the simplicity of preparing a home-cooked meal. When you see fractions presented in the form ‘a:b’, you’re observing a ratio. Conversely, when two such ratios equate, they form a proportion. And these concepts aren’t just restricted to math; they find resonance in science too.

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Our goal? To dispel any confusion and arm our readers with the clarity and knowledge needed to tackle ratio and proportion questions head-on. As we delve deeper into this article, you’ll discover an array of solved examples, and a revisit of previous year ratio and proportion questions, to fortify your understanding.

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260+ Most Asked Ratio And Proportion Questions

251. 40% of the students in the class scored the mark in below 80 and the ratio of the number of students scored above 80 to exactly 80 marks in 3:4. If the number of students scored the marks exactly 80 is 12, then find the total number of students in the class?

कक्षा में छात्रों के 40% ने 80 से नीचे के अंकों को प्राप्त किया और 80 से ऊपर से पूर्णतया 80 अंकों को प्राप्त करने वाले छात्रों की संख्या का अनुपात 3: 4 में है। यदि पूर्णतया 80 अंकों को प्राप्त करने वाले छात्रों की संख्या 12 है, तो कक्षा में छात्रों की कुल संख्या को ज्ञात कीजिए?

A. 40
B. 45
C. 35
D. 30
E. 50

Option “C” is correct.

Number of students scored above 80 = 3/4 * 12 = 9

40% of the students scored below 80, so 60% of the students scored above 80 and exactly 80 marks.

Number of students scored below 80 = 40/60 * (9 + 12) = 14

Total number of students = 14 + 9 + 12 = 35

252. Anil took four papers in an examination, where each paper was of 100 marks. His marks in these papers were in the proportion of 10: 12: 15: 16. In all papers together, Anil got 66.25% of the total marks. Then the number of papers in which he got more than 50% of marks is ?

अनिल ने एक परीक्षा में चार पेपर लिए, जिसमें प्रत्येक पेपर 100 अंकों का था। इन पेपर में उनके अंक 10: 12: 15: 16 के अनुपात में थे। सभी पेपर में कुल मिलाकर अनिल को कुल अंकों का 66.25% मिला। फिर 50% से अधिक अंक पाने वाले पेपरों की संख्या कितनी है?

A. 2
B. 3
C. 4
D. 1
E. None of these

Option “B” is correct.

10x + 12x + 15x + 16x = 66.25/100 (100 * 4)

=> x = 5

Hence, marks obtained in 3 papers are more than 50%.

253. The sum of the total mark scored by A, B and C is 86 and the ratio of the mark scored by B to C is 3:2. If the square of the mark scored by B is 500 more than the square of the mark scored by C, then find the mark scored by A?

A, B और C द्वारा प्राप्त किए गए कुल अंकों का योग 86 है और B से C द्वारा प्राप्त अंकों का अनुपात 3:2 है। यदि B द्वारा प्राप्त अंक का वर्ग C द्वारा प्राप्त अंक के वर्ग से 500 अधिक है, तो A द्वारा प्राप्त अंक ज्ञात कीजिये?

A. 36
B. 24
C. 48
D. 50
E. None of these

Option “A” is correct.

Let the mark scored by B = 3x

And the mark scored by C = 2x

(3x)2 – (2x)2 = 500

9x2 – 4x2 = 500

x2 = 100

x = 10

The mark scored by B = 3 * 10 = 30

The mark scored by C = 2 * 10 = 20

The mark scored by A = 86 – 30 – 20 = 36

254. Ratio of the mark scored by Anu to Bala in the exam is 5:7 and Anu scored 65% of the maximum marks. If the difference between the mark scored by Anu and Bala is 52, then find the maximum marks in the exam.

परीक्षा में अनु से बाला द्वारा प्राप्त अंकों का अनुपात 5:7 है और अनु ने अधिकतम अंकों का 65% प्राप्त किया। यदि अनु और बाला द्वारा प्राप्त अंकों के बीच का अंतर 52 है, तो परीक्षा में अधिकतम अंक ज्ञात कीजिए।

A. 150
B. 300
C. 200
D. 120
E. None of these

Option “C” is correct.

The mark scored by Anu = 52 * 5x/(7x – 5x) = 52 * 5x/2x = 130

The maximum marks in the exam = 130 * 100/65 = 200

255. Ratio of the mark obtained by Mohan in English,Physics and Hindi is 3:4:6 respectively and the mark obtained by Mohan in Chemistry is 250. If the maximum mark in each subject is 300 and the overall percentage of marks obtained by Mohan in all four subjects is 75%, then find the mark obtained by Mohan in English.

मोहन द्वारा अंग्रेजी, भौतिकी और हिंदी में प्राप्त अंकों का अनुपात क्रमशः 3:4:6 है और मोहन द्वारा रसायन विज्ञान में प्राप्त अंक 250 है। यदि प्रत्येक विषय में अधिकतम अंक 300 हैं और मोहन द्वारा सभी चार विषयों में प्राप्त अंकों का कुल प्रतिशत 75% प्रतिशत है, तो मोहन द्वारा अंग्रेजी में प्राप्त अंक ज्ञात कीजिए।

A. 210
B. 150
C. 180
D. 240
E. None of these

Option “B” is correct.

The overall marks obtained by Mohan in all four subjects = (300 * 4) * 75/100 = 900

3x + 4x + 6x = 900 – 250

x = 650/13 = 50

The mark obtained by Mohan in English = 3 * 50 = 150

256. In an exam, the ratio of the mark scored by A to B is 3:4 and the ratio of the mark scored by A to C is 5:6. If the maximum score in the exam is 150 and the difference of mark scored by A and B is 30, then what is the percentage of mark scored by C.

एक परीक्षा में, A से B के प्राप्त अंकों का अनुपात 3:4 है और A से C द्वारा प्राप्त अंकों का अनुपात 5:6 है। यदि परीक्षा में अधिकतम अंक 150 है और A और B द्वारा प्राप्त अंकों का अंतर 30 है, तो C द्वारा प्राप्त अंकों का प्रतिशत क्या है?

A. 60%
B. 84%
C. 54%
D. 72%
E. None of these

Option “D” is correct.

4x – 3x = 30

x = 30

The mark scored by A = 3 * 30 = 90

The mark scored by C = 90 * 6/5 = 108

Required percentage = 108/150 * 100 = 72%

257. In an exam, the mark scored by M is 7/9th of the mark scored by N and ratio of the mark scored by N to L is 5:6 and the pass mark is 30. If the score of M is increased by 4, then the mark scored by M is 130% of the pass mark. Find the sum of the mark scored by N and L together.

एक परीक्षा में, M द्वारा प्राप्त अंक, N द्वारा प्राप्त अंक का 7/9वां है और N से L द्वारा प्राप्त अंक का अनुपात 5:6 है और उत्तीर्ण अंक 30 है। यदि M के अंक को 4 से बढ़ा दिया जाता है, तो M द्वारा प्राप्त अंक उत्तीर्ण अंक का 130% है। एकसाथ N और L द्वारा प्राप्त अंकों का योग ज्ञात कीजिए।

A. 99
B. 88
C. 110
D. 72
E. None of these

Option “A” is correct.

The mark scored by M initially = 30 * 130/100 – 4 = 39 – 4 = 35

The mark scored by N = 35 * 9/7 = 45

The mark scored by L = 45 * 6/5 = 54

Required sum L and N = 45 + 54 = 99

258. Ratio of the mark scored by Ravi to Savi in the exam is 3:x and the mark scored by Pavi in the exam is 4/5th of the mark scored by Ravi. If the sum of the mark scored by Ravi, Savi and Pavi together is 235 and the difference of the mark scored by Pavi and Ravi is 15, then find the value of x.

परीक्षा में रवि से सवी द्वारा प्राप्त अंक का अनुपात 3: x है और परीक्षा में पावी द्वारा प्राप्त अंक रवि द्वारा प्राप्त अंक का 4/5 है। यदि एक साथ रवि, सवी और पावी द्वारा प्राप्त अंकों का योग 235 है और पावी और रवि द्वारा प्राप्त अंकों का अंतर 15 है, तो x का मान ज्ञात कीजिए।

A. 1
B. 4
C. 7
D. 3
E. None of these

Option “B” is correct.

5x – 4x = 15

x = 15

The mark scored by Ravi = 5 * 15 = 75

The mark scored by Pavi = 4 * 15 = 60

The mark scored by Savi = 235 – 75 – 60 = 100

3/x = 75/100

x = 4

259. The pass mark in the exam is 75 and the ratio of the mark obtained by P to Q in the exam is 7:4. If the mark obtained by P is 40% more than the pass mark, then find the ratio of the mark obtained by Q to the pass mark in the exam.

परीक्षा में उत्तीर्ण अंक 75 है और परीक्षा में P से Q द्वारा प्राप्त अंकों का अनुपात 7:4 है। यदि P द्वारा प्राप्त अंक उत्तीर्ण अंक से 40% अधिक है, तो परीक्षा में Q द्वारा प्राप्त अंक से उत्तीर्ण अंक का अनुपात ज्ञात कीजिए।

A. 2:3
B. 1:3
C. 4:5
D. 11:15
E. None of these

Option “C” is correct.

The mark obtained by P = 75 * 140/100 = 105

The mark obtained by Q = 105 * 4/7 = 60

Required ratio = 60:75 = 4:5

260. Kamal obtained x marks in the exam and failed the exam by 5 marks and Kalam obtained (x+15) marks in the exam and the pass percentage is 50% of the maximum marks. If the ratio of the mark obtained by Kalam to Kamal is 4:3, then find the maximum marks in the exam.

कमल ने परीक्षा में x अंक प्राप्त किए और परीक्षा में 5 अंकों से अनुत्तीर्ण हो गया और कलाम ने परीक्षा में (x+15) अंक प्राप्त किए और उत्तीर्ण प्रतिशत अधिकतम अंकों का 50% है। यदि कलाम से कमल द्वारा प्राप्त अंकों का अनुपात 4:3 है, तो परीक्षा में अधिकतम अंक ज्ञात कीजिए।

A. 50
B. 120
C. 80
D. 100
E. None of these

Option “D” is correct.

x/(x + 15) = 3/4

4x = 3x + 45

x = 45

The mark obtained by Kamal = 45

The pass mark of the exam = 45 + 5 = 50

The maximum marks = 50 * 100/50 = 100

 

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