Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

91. A bike covers a certain distance at a speed of 56 km/hr in 16 hours. How much time it will take to cover the same distance at the speed of 64 km/hr?

एक मोटरसाइकिल 16 घंटे में 56 किमी/घंटा की गति से एक निश्चित दूरी तय करती है। 64 किमी/घंटा की गति से समान दूरी तय करने में कितना समय लगेगा?

Option “A” is correct.

Distance covered at 56 km/hour = 56 × 16 = 896 km

New speed = 64 km/hour

Distance is same as previous,

 Time = 896/64 = 14 hour

∴ 14 hours it will take to cover the same distance at the speed of 64 km/hr

92. How many minutes does a car take to cover a distance of 200 m, if it runs at a speed of 60 kmph?

60 किलोमीटर प्रति घंटे की गति से चलने वाली कार को 200 मीटर की दूरी तय करने में कितने मिनट लगते हैं?

Option “B” is correct.

Let the time taken by car to cover 200 m be ‘t’ minute

⇒ speed = 60 km/hr = 300/18 m/s

⇒ time = 200 × 18/300 = 12 s = 1/5 min 

∴ required time = 1/5 min

93. Rahul starts to walk from P towards Q at 11 am and Akash starts to walk from Q towards P at 11 am and after meeting at X they both will reach their destinations in 36 and 49 minutes, then find out at which time they will meet at X.

राहुल पूर्वाह्न 11 बजे P से Q की ओर चलना प्रारंभ करता है और आकाश पूर्वाह्न 11 बजे Q से P की तरफ चलना प्रारंभ करता है और X पर मिलने के बाद वे दोनों अपने गंतव्य पर 36 और 49 मिनट में पहुचेंगे, तब ज्ञात कीजिये किस समय वे X पर मिलेंगे।

Option “D” is correct.

When Rahul and Akash meet at X and reach their destinations in respective time, then the time at which they will meet at X is,

t = √(time taken by Rahul to reach his destination after meeting Akash at X × time taken by Akash to reach his destination after meeting Rahul at X)

⇒ meeting time, t = √(36 × 49) = 42 minutes.

∴ They will meet at 11:42 am.

94. The distance between two points A and B is 20 km. Two dogs barked and ran towards each other, one from A to B and the other from B to A. They cross each other after 30 minutes and the first dog reaches B, 80 minutes before the second dog reaches A. Find the difference between the speeds of both dogs.

दो बिंदु A और B के बीच की दूरी 20 किमी है। दो कुत्ते भौंकते हैं और एक-दूसरे की ओर भागते हैं, एक A से B की ओर और दूसरा B से A की ओर। वे 30 मिनट के बाद एक-दूसरे को पार करते हैं और पहला कुत्ता, दूसरे कुत्ते के A तक पहुंचने से 80 मिनट पहले B तक पहुंचता है। दोनों कुत्तों के गति के बीच अंतर ज्ञात कीजिए।

Option “D” is correct.

Let the speed of the slower dog is ‘s’ and the faster dog is ‘f’

Then, according to the question,

f + s = 20/0.5 = 40     —-(1)

And,

Let the time taken by the faster dog is X and for the slower dog, it is X+80.

Difference in time  = 80 minutes

(20/s) – (20/f) = 80/60     —-(2)

After solving these two equations, we will get:

⇒ s = 10

⇒ f = 30

∴ Required difference = 30 – 10 = 20 km/h

95. Two cities X and Y are 800 km apart. A bus started from city X at a speed of 65 km/hr. to reach city Y, while another bus started at the same time from city Y at a speed of 60 km/hr. to reach city X. What is the difference between the distances covered by the two buses to reach their meeting point?

दो शहर X और Y 800 किमी दूर हैं। शहर Y तक पहुंचने के लिए एक बस 65 किमी/घंटा की गति से शहर X से शुरू हुई, जबकि दूसरी बस शहर Y से 60 किमी/घंटा की गति से शहर X तक पहुंचने के लिए उसी समय शुरू हुई। दोनों बसों द्वारा अपने संगम बिंदु तक पहुंचने के लिए तय की गई दूरियों के बीच अंतर क्या है?

Option “B” is correct.

∵ The two buses are moving towards each other, i.e., in opposite direction, their relative speed is the sum of their individual speeds

⇒ Relative speed of buses = 65 + 60 = 125 km/hr.

∵ The buses had together covered the whole distance of 800 km to reach their meeting point,

⇒ Time taken to reach meeting point = 800/125 = 6.4 hrs.

Now,

Distance covered by first bus to reach meeting point = 65 × 6.4 = 416 km

Distance covered by second bus to reach meeting point = 60 × 6.4 = 384 km

∴ Required difference = 416 – 384 = 32 km

96. The distance between Allahabad railway station and Delhi railway station is 720 km. Shiv Ganga train starts from Allahabad and moves towards Delhi at 40 km/hr and another train Garib Rath train starts from Delhi and moves towards Allahabad. Speed of Garib Rath is 25% more than the speed of Shiv Ganga. How far from Allahabad they cross each other?

अलाहाबाद और दिल्ली रेलवे स्टेशन में 720 किमी की दूरी है। शिव गंगा ट्रेन अलाहाबाद से शुरू होती है और दिल्ली की ओर 40 किमी/घंटा की गति से आगे बढ़ती है। और एक अन्य रेलगाड़ी गरीब रथ दिल्ली से शुरू होती है और अलाहाबाद की ओर बढ़ती है। गरीब रथ की गति, शिव गंगा से 25% अधिक है। अलाहाबाद से कितनी दूरी पर ये दोनों रेलगाड़ियाँ एक दूसरे को पार करेंगी?

Option “B” is correct.

Speed of Shiv Ganga train = 40 km/h

Speed of Garib Rath train = 40 × [5/4] = 50 km/h

Distance between two station Allahabad and Garbi Rath = 720 km

Shiv Ganga and Garib Rath’s relative speed = (40 + 50) = 90 km/h

Shiv Ganga and Garib Rath will meet each other in = 720/90 = 8 hrs

Shiv Ganga will cover the distance in 8 hrs = 8 × 40 = 320 km/h

Both train cross each other 320 km from Allahabad.

97.Travelling at 60 km/h, a person reaches his destination at a certain time. He covers 60% of his journey in 2/5th of the time. At what speed (in km/h) should he travel to cover the remaining journey so that he reaches the destination right on time?

60 किमी/घंटा की गति से चलते हुए एक व्यक्ति विशिष्ट समय अपने गंतव्य पर पहुँचता है। वह अपनी यात्रा का 60% भाग 2/5 समय में तय कर लेता है। अपने गंतव्य पर सही समय से पहुँचने के लिए उसे शेष यात्रा किस गति से (किमी/घंटा में) पूरी करनी चाहिए?

Option “C” is correct.

Let the total time be 5 hours.

Speed of the person = 60km/h

Total distance = 5 × 60 = 300

He covers 60% of his journey in 2/5th of the time

Remaining journey = 300 × (40/100) = 120 km

Remaining time = 5 × (3/5) = 3 hr

Required speed = 120/3 = 40 km/h

98. A man starts from his house and travelling at 30 km/h, he reaches his office late by 10 minutes, and travelling at 24 km/h, he reaches his office late by 18 minutes. The distance (in km) from his house to his office is∶

एक आदमी अपने घर से यात्रा शुरू करता है और 30 किमी/घंटा की गति से यात्रा करते हुए वह अपने कार्यालय 10 मिनट की देरी से पहुँचता है और 24 किमी/घंटा की गति से यात्रा करते हुए वह अपने कार्यालय 18 मिनट की देरी से पहुँचता है। उसके घर से उसके कार्यालय की दूरी (किलोमीटर में) कितनी है?

Option “D” is correct.

As we know,

Distance = Time × Speed

Let correct taking time to reach his office be x hr

30 × (x + 10/60) = 24 × (x + 18/60)

⇒ 30x + 5 = 24x + 36/5

⇒ 30x – 24x = 36/5 – 5

⇒ 6x = 11/5

⇒ x = 11/30 hr

Required distance = 30 × (11/30 + 10/60) = 30 × (22 + 10)/60 = 16 km

99. A bus started from city X towards city Y at 9 ∶ 15 AM at a speed of 48 km/hr, while another bus started from city Y towards city X at 10 ∶ 30 AM at a speed of 60 km/hr. If they cross each other at 1 ∶ 45 PM, find the distance between the cities X and Y?

एक बस शहर X से शहर Y के लिए 9:15 पूर्वाहन पर 48 किमी/घंटा की गति से चलना शुरू करती है, जबकि एक अन्य बस शहर Y से शहर X के लिए 10:30 पूर्वाहन पर 60 किमी/घंटा की गति से चलना शुरू करती है। यदि वह एक दूसरे को 1:45 अपराहन पर पार करती है, तो शहर X और शहर Y के बीच दूरी ज्ञात कीजिये?

Option “A” is correct.

From 9 ∶ 15 AM to 1 ∶ 45 PM, the bus from city X travelled for 4 hrs. 30 min. = 4 + 30/60 = 4.5 hrs.

Speed of bus from city X = 48 km/hr

Formula∶ Distance = Speed × Time

⇒ Distance covered by bus from city X in 4.5 hrs. = 48 × 4.5 = 216 km

Similarly,

From 10 ∶ 30 AM to 1 ∶ 45 PM, the bus from city Y travelled for 3 hrs. 15 min. = 3 + 15/60 = 3.25 hrs

Speed of bus from city Y = 60 km/hr

⇒ Distance covered by bus from city Y in 3.25 hrs. = 60 × 3.25 = 195 km

∵ Distance between two cities = Sum of distances covered by the buses till the meeting point

∴ Distance between cities X & Y = 216 + 195 = 411 km

100. A fighter plane F-16 is noticed by a fighter plane M-21 from a distance of 300 km. The fighter plane F-16 starts running and fighter plane M-21 chases him. The fighter plane F-16 and fighter plane M-21 run at the rate of 900 km/ hour and 990 km/hour respectively. What is the distance between them after 10 seconds?

एक लड़ाकू विमान F-16 को 300 किमी की दूरी से एक लड़ाकू विमान M-21 द्वारा देखा जाता है। लड़ाकू विमान F-16 चलने लगता है और लड़ाकू विमान M-21 उसका पीछा करता है। लड़ाकू विमान F-16 और लड़ाकू विमान M-21 क्रमशः 900 किमी/घंटा और 990 किमी/घंटे की दर से चलते हैं। 10 सेकंड के बाद उनके बीच की दूरी क्या है?

Option “D” is correct.

Distance covered by fighter plane F-16 in 10 seconds,

⇒ D1 = 900 × 10 × (5/18) = 2500 meters = 2.5 km

⇒ Distance covered by fighter plane M-21 in 10 seconds,

⇒ D2 = 990 × 10 × (5/18) = 2750 meters = 2.75 km

∴ The distance between them after 10 seconds = 300 – (2.75 – 2.5) = 300 – 0.25 = 299.75 km

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