Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

111. A policeman spots the thief at a distance of 100 m running away at a speed of 12 km/h. The policeman waits for 1 minute and then starts chasing the thief at a speed of 16 km/h. How much time will be taken by the policeman to catch the thief?

एक पुलिसकर्मी 100 मीटर की दूरी पर 12 किमी/घंटे की गति से भागते हुए चोर को देखता है। पुलिसकर्मी 1 मिनट तक इंतजार करता है और फिर 16 किमी/घंटे की गति से चोर का पीछा करना शुरू कर देता है। चोर को पकड़ने में पुलिसकर्मी को कितना समय लगेगा?

Option “B” is correct.

Since the thief has a head-start of 100 metres, and also 1 minute ( = 60 seconds)

⇒ Distance covered by the thief before the policeman starts chasing = 10/3 × 60

⇒ Distance covered = 200 metres

⇒ The thief has a head start of 300 meters ( = 100 + 200).

⇒ the relative speed = 40/9 – 10/3

⇒ the relative speed = 10/9 m/s

⇒ Time taken by the policeman to catch the thief = 300/(10/9)

⇒ Time taken by the policeman to catch the thief = 270 seconds (or 4.5 minutes)

112. Two men started at the same time, one from Uttar Pradesh to Goa and the other from Goa to Uttar Pradesh. If they arrived at Goa and Uttar Pradesh respectively, 225 hrs and 256 hrs after they crossed each other, if the speed of the first man was 40 km, then the speed of the other man was? 

दो आदमी एक ही समय में यात्रा शुरू करते हैं, एक उत्तर प्रदेश से गोवा और दूसरा गोवा से उत्तर प्रदेश। यदि वे एक-दूसरे को पार करने के बाद क्रमशः 225 घंटे और 256 घंटे में गोवा और उत्तर प्रदेश पहुंचे, तो यदि पहले आदमी की गति 40 किमी थी, तो दूसरे आदमी की गति क्या थी?

Option “D” is correct.

Let t1 = 225 and t2 = 256

Let speed other man be x km/hr respectively,

According to the question

(40/x)2 = (256/225)

⇒ 40/x = √256/225

⇒ 40/x = 16/15

⇒ x = 40 × (15/16)

⇒ x = 37.5 km/hr

∴ Speed of other man was 37.5 km/hr.

113. Two men started at the same time, one from Uttar Pradesh to Goa and the other from Goa to Uttar Pradesh. If they arrived at Goa and Uttar Pradesh respectively, 225 hrs and 256 hrs after they crossed each other, if the speed of the first man was 40 km, then the speed of the other man was? 

दो आदमी एक ही समय में यात्रा शुरू करते हैं, एक उत्तर प्रदेश से गोवा और दूसरा गोवा से उत्तर प्रदेश। यदि वे एक-दूसरे को पार करने के बाद क्रमशः 225 घंटे और 256 घंटे में गोवा और उत्तर प्रदेश पहुंचे, तो यदि पहले आदमी की गति 40 किमी थी, तो दूसरे आदमी की गति क्या थी?

Option “D” is correct.

Let t1 = 225 and t2 = 256

Let speed other man be x km/hr respectively,

According to the question

(40/x)2 = (256/225)

⇒ 40/x = √256/225

⇒ 40/x = 16/15

⇒ x = 40 × (15/16)

⇒ x = 37.5 km/hr

∴ Speed of other man was 37.5 km/hr.

114. Two cars are initially 64 km apart and speed of cars is 48 km/h  and ‘x’ km/h . Distance between them will be 4 km after travelling for ‘t1’ min when travelling towards each other and distance between them will be 84 km after ‘t2’ min when travelling away from each other. If ‘t1 – t2’ is 30, then find the speed of second car.

दो कारें शुरू में 64 किमी दूर हैं और कारों की गति 48 किमी/घंटा और ‘x’ किमी/घंटा है। एक दूसरे की ओर यात्रा करते समय ‘t1‘ मिनट की यात्रा के बाद उनके बीच की दूरी 4 किमी होगी और एक दूसरे से दूर यात्रा करते समय उनके बीच की दूरी ‘t2‘ मिनट के बाद 84 किमी होगी। यदि ‘t1 – t2’ का मान 30 है, तो दूसरी कार की गति ज्ञात कीजिए।

Option “D” is correct.

Let speed of second car = ‘x’

Relative speed of cars = (48 + x)

From (1) and (2):

t1 / t2 = 3 / 1

Let t1 = 3a and t2 = a

t1 – t2 = 30

⇒ 3a – a = 30

⇒ a = 15

From equation (1):

(48 + x) × 3 × 15 = 3600

⇒ 48 + x = 80

⇒ x = 32

∴ Speed of second car = x = 32 km/h 

115. In 440 m race P beats Q by 110 m or 9 seconds. Find the time taken by P to finish the race?

440 मीटर दौड़ में P, Q को 110 मीटर या 9 सेकंड से हरा देता है। दौड़ समाप्त करने के लिए P द्वारा लिया हुआ समय ज्ञात कीजिए?

Option “A” is correct.

Q covers the distance of 110 m in 9 seconds.

∴ Time taken to cover 440m = (9/110) × 440 = 36 seconds

So, Q rakes 36 seconds to cover 440m and P wins by 9 seconds

∴ Time taken by P = 36 – 9 = 27 seconds

116. A 15 m long bus crosses a 75 m long bridge in 6 seconds. In how much time will it cross a man running in the same direction at a speed of 9 km/hr?

एक 15 मीटर लंबी बस 6 सेकंड में 75 मीटर लंबे पुल को पार कर जाती है। 9 किमी/घंटा की गति से एक ही दिशा में भागने वाले व्यक्ति को यह कितने समय में पार करेगी?

Option “D” is correct.

Time taken by bus to cross the bridge = Sum of length of bus & bridge/Speed of bus

⇒ 6 = (15 + 75)/Speed of bus

⇒ Speed of bus = 90/6 = 15 m/sec

Now,

Speed of man = 9 km/hr = 9 × 5/18 = 2.5 m/sec

∵ The man is running in the same direction as the bus, their relative speed is the difference of their individual speeds

⇒ Relative speed = 15 – 2.5 = 12.5 m/sec

⇒ Time taken by bus to cross the man = Length of bus/Relative speed

∴ Tome taken by bus to cross the man = 15/12.5 = 1.2 seconds

117.If Raj travels at speed of 24 km/hr, he reaches his destination 15 minutes late, however if he travels at speed of 26 km/hr, he reaches his destination 20 minutes early. Find the time taken by Raj to reach destination if he travels at speed of 13 km/hr.

यदि राज 24 किमी/घंटे की गति से यात्रा करता है, वह अपने गंतव्य तक 15 मिनट देर से पहुँचता है, हालांकि यदि वह 26 किमी/घंटे की गति से यात्रा करता है, वह अपने गंतव्य तक 20 मिनट पहले पहुँच जाता है। राज द्वारा गंतव्य तक पहुँचने में लिया गया समय ज्ञात कीजिए, यदि वह 13किमी/घंटे की गति से यात्रा करता है।

Option “A” is correct.

Let distance between his destination and home be A km.

Difference in time taken by Raj = 20 + 15 = 35 min = 35/60 hr = 7/12

Then,

⇒ A/24 – A/26 = 7/12

Solving,

⇒ A = 182 km

Speed = 13 km/hr

Time taken = 182/13

= 14 hr

118. A train travelling at 44 km/h crosses a man walking with a speed of 8 km/h, in the same direction, in 15 seconds. If the train crosses a woman coming from the opposite direction in 10 seconds, then what is the speed (in km/h) of the woman?

44 किमी / घंटा की गति से यात्रा करने वाली ट्रेन 8 किमी / घंटा की गति से चलने वाले आदमी को समान दिशा में, 15 सेकंड में पार करती है। यदि ट्रेन 10 सेकंड में विपरीत दिशा से आने वाली महिला को पार करती है, तो महिला की गति (किमी / घंटा में) क्या है?

Option “D” is correct.

Speed of the train = 44 km/h & Speed of the man = 8 km/h

⇒ Length of the train = (44 – 8) × (5/18) × 15 = 150 meters

Let the speed of the woman be x km/h

According to the question

⇒ (44 + x) × 5/18 = 150/10

⇒ (44 + x) = 54

⇒ x = 10 km/h

119. Train A which was travelling at 50 km/h crosses train B travelling in opposite direction in 15 seconds. If the length of train B is three times the length of A and the speed of train B was 58 km/h, then the length of train A(in m) is∶

ट्रेन A जो 50 किमी/घंटा की गति से चल रही थी। एक अन्य ट्रेन, B, जिसकी लंबाई A की लंबाई से तीन गुना थी, ने उसे 15 सेकंड में विपरीत दिशा में पार किया। यदि ट्रेन B की गति 58 किमी/घंटा थी, तो ट्रेन A की लंबाई (मीटर में) क्या है?

Option “B” is correct.

Let the length of the train A be x m

Length of the train B = 3x

Speed of the train A = 50 km/hr

Speed of the train B = 58 km/hr

Effective speed of both train = 50 + 58 = 108 km/hr

As we know,

Speed = Distance/Time

108 × (5/18) = (3x + x)/15

⇒ 30 = 4x/15

⇒ x = 450/4 = 112.5 m

120. Raj travels on a cycle of length 1.6 m with a speed of 9 km/h. B travels on a bike of length 1.8 m and crosses a bridge of length 100 m in 50.9 seconds. In what time Raj will cross B when they are travelling in the same direction?

राज 9 किमी/घंटे की गति के साथ लंबाई 1.6 मीटर की साइकिल पर यात्रा करता है। B लंबाई 1.8 मीटर की बाइक पर यात्रा करता है और 50.9 सेकंड में लंबाई 100 मीटर का पुल पार करता है। जब वे समान दिशा में यात्रा कर रहे होंगे तो राज किस समय B को पार करेगा?

Option “A” is correct.

Given,

Speed of Raj’s cycle = 9 × 5/18 = 2.5 m/s

Length of cycle = 1.6 m

Length of bike = 1.8 m

Length of bridge = 100 m

Speed of B’s bike = (100 + 1.8)/50.9 = 2 m/s

Relative speed = 2.5 – 2 = 0.5 m/s

Required time = (1.6 + 1.8)/0.5 = 6.8 seconds

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