Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

11. Aman goes with a speed of 27 km/hr from Delhi to Agra and comes back to Delhi with a speed of 33 km/hr. Find the average speed of Aman during the whole journey.

अमन दिल्ली से आगरा तक 27 किमी/घंटा की गति से जाता है और 33 किमी/घंटा की गति के साथ वापस दिल्ली आता है। पूरी यात्रा में अमन की औसत गति ज्ञात कीजिए।

Option “A” is correct.

Average speed = 2 × A × B/(A + B)

⇒ 2 × 27 × 33/(27 + 33)

⇒ 1782/60

⇒ 29.7 km/hr

 The average speed of Aman in the whole journey is 29.7 km/hr.

12. Find the average speed of a boy if he walks 1/3rd distance with a speed of 2 m/sec and rides a bike to cover the remaining distance with a speed of 12 m/s. The total distance is 1.44 km.

एक लड़के की औसत गति ज्ञात कीजिए, यदि वह दूरी का 1/3 भाग 2 मी/से की गति से चलता है और शेष दूरी को तय करने के लिए 12 मी/से की गति से बाइक चलाता है। कुल दूरी 1.44 किमी है।

Option “D” is correct.

⇒ Distance covered on foot = 1.44/3 = 0.48 km = 480 m

⇒ Distance covered on bike = 1440 – 480 = 960 m

As,

⇒ Time = distance/speed

⇒ Total Time taken = (480/2) + (960/12) = 240 + 80 = 320 sec

∴ Average speed = Total distance/total time = (1.44/320) × 3600 = 16.2 km/hr

13. A train without stoppage travels with an average speed of 70 km/h, and with stoppage, it travels with the average speed of 56 km/h. How many minutes, does the train stop on an average per hour?

एक ट्रेन बिना रुके 70 किमी/घंटा की औसत गति के साथ यात्रा करती है, और स्टॉपेज के साथ, यह 56 किमी/घंटा की औसत गति के साथ यात्रा करती है। प्रति घंटे औसतन ट्रेन कितने मिनट रुकती है?

Option “A” is correct.

Without stoppage average speed = 70 km/h

With stoppages average speed = 56 km/h

As we know,

Time of rest per hour equal to the difference in average speed divided by the speed without stoppage.

∴ Required time = [(70 – 56)/70] × 60 = 12

So, A train stops on an average 12 minute/h.

14. A train goes from P to Q with a speed u km/h, then from Q to R (QR = 2PQ) with a speed 3u km/h, and returns from R to P With a speed u/2 km/h. What is the average speed (in km/h) of the train for the entire journey starting from P and back to P?

एक ट्रेन P से Q तक u किमी/घंटा की गति से चलती है, फिर Q से R तक (QR = 2PQ) 3u किमी/घंटा, और R से P तक u/2 किमी/घंटा की गति से वापस आती है। P से प्रारंभ करते हुए वापस P तक की कुल यात्रा में ट्रेन की औसत गति (किमी/घंटा) कितनी है?

Option “A” is correct.

Let the distance between P to Q be d.

⇒ QR = 2d

⇒ RP = 3d

Average speed = total distance/total time

Total time = distance/speed

Time taken by train from P to Q = d/u

Time taken by train from Q to R = 2d/3u

Time taken by train from R to P = 3d/(u/2) = 6d/u

Total time = d/u + 2d/3u + 6d/u = 23d/3u

Total distance = d + 2d + 3d = 6d

Average speed = 6d/(23d/3u) = 18u/23

15. Shiv travels at the speed of 5 km/hr, 8 km/hr and 10 km/hr for three equal distances. What is his average speed if the total distance travelled by him is 120 km?

शिव तीन समान दूरी के लिए 5 किमी/घंटा, 8 किमी/घंटा और 10 किमी/घंटा की गति से यात्रा करता है। यदि उसकी कुल दूरी 120 किमी है तो उसकी औसत गति क्या है?

Option “B” is correct.

⇒ The equal distance travel by Shiv = 120/3 = 40 km

⇒ Total time taken by him to travel 120 kms = 40/5 + 40/8 + 40/10 = 8 + 5 + 4 = 17 hours

⇒ Average speed = Total distance travelled/Total time taken

⇒ Average speed = 120/17 = 7.05 km/hr

16. A car travels with a speed of 18 m/second for one third of the total time of the journey and then it travels with a speed of 25 m/second for 60% of the remaining time and then travels with a speed of V for rest of the time. If the average speed of the car is 24 m/second then find the value of V in km/hour.

एक कार यात्रा के कुल समय के एक तिहाई के लिए 18 मीटर/सेकंड की चाल के साथ यात्रा करती है और फिर शेष समय के 60% के लिए 25 मीटर/सेकंड की चाल के साथ यात्रा करती है और फिर शेष समय के लिए V की चाल के साथ यात्रा करती है। यदि कार की औसत चाल 24 मीटर/सेकंड है तो किमी/घंटे में V का मान ज्ञात कीजिए।

Option “D” is correct.

Let the total time taken be t second

According to question,

1st period of time = t/3

Distance covered in this period = t/3 × 18 = 6t m

2nd period of time = 2t/3 × 60% = 2t/5

Distance covered in this period = 2t/5 × 25 = 10t m

And 3rd period of time = 2t/3 – 2t/5 = 4t/15

Distance covered in this period = 4t/15 × V = 4Vt/15 m

Now,

As we know, average speed = (total distance covered) / (total time taken)

24 = (6t + 10t + 4Vt/15)/t

⇒ 16t + 4Vt/15 = 24t

⇒ 4Vt/15 = 8t

⇒ V = 30 m/second

So V = 30 × 18/5 km/hour

Hence, 108 km/hour

17.A car can travel a distance of 300 meters in 6 minutes. What is its average speed in km/h?

एक कार 6 मिनट में 300 मीटर की दूरी तय कर सकती है। किमी/घंटा में उसकी औसत गति क्या है?

Option “D” is correct.

Distance = 300 meters = 0.3 km

⇒ Time = 6 minutes = 0.1 hour

⇒ Speed = distance/ time = 0.3/0.1 = 3 km/h

∴ The average speed of car is 3 in km/h.

18. Aman and Ayush start travelling in same direction at 6 km/hr and 10 km/hr respectively. After 5 hours, Aman doubled his speed and Ayush reduced his speed by 2 km/hr and reached the destination together. How long the entire journey last?

अमन और आयुष समान दिशा में क्रमशः 6 किमी/घंटा और 10 किमी/घंटा की गति से चलना प्रारंभ करते हैं। 5 घंटों के बाद, अमन अपनी गति दोगुनी करता है और आयुष अपनी गति से 2 किमी/घंटा की कमी करता है और दोनों एकसाथ गंतव्य पर पहुँचते हैं। पूरी यात्रा कितने समय तक चलती है?

Option “B” is correct.

Let the journey lasted for x hrs.

According to problem,

⇒ 6 × 5 + 6 × 2 × (x – 5) = 10 × 5 + (10 – 2) × (x – 5)

⇒ 30 + 12x – 60 = 50 + 8x – 40

⇒ 4x = 40

⇒ x = 10

∴ Journey lasted for 10 hours

19. A man driving bike at 72 km per hour. However, he takes small breaks each of 3 minutes after every 20 minutes of his drive. How much distance the man will cover in 100 minutes?

एक आदमी 72 किमी प्रति घंटे की गति से एक बाइक चलाता है। हालाँकि, वह अपनी ड्राइव के प्रत्येक 20 मिनट के बाद 3 मिनट के छोटे ब्रेक लेता है। 100 मिनट में आदमी कितनी दूरी तय करेगा?

Option “B” is correct.

After every 20 minutes he rests for 3 min

In 100 minutes he waits for 100/20 = 5 times (only 4)

As last 20 minute will be stoppage

∴ In 100 min he rests for 3 × 4= 12 min

∴ He actually travelled for = (100 – 12) = 88 min

∴ Distance covered by him = 72 × 88/60 = 105.6 km

∴ The man will cover 105.6 km in 100 minutes.

20. A car travels from A to B with 40 Km/h and returns from B to A with 60 Km/h. Its average speed during the whole journey is
      एक गाड़ी A से B तक 40 किमी/घंटे की गति से जाती है और B से A तक 60 किमी/घंटे की गति से वापस आती है। सम्पूर्ण यात्रा के दौरान उसकी औसत गति है:

Option “A” is correct.

As we know,

Average speed = 2xy/(x + y)

∴ Average speed = (2 × 40 × 60)/(40 + 60) = 48 km/hr

Click here to Practice Previous year 10000+ Questions of Quantitative Aptitude
Click here to Practice Get Free E-books and notes of All Subjects