Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

21. Mahima started a journey 12 minutes late and as a result, had to drive @54 km/hr instead of @45 km/hr to reach on time. Find the distance covered during the journey.

महिमा एक यात्रा को 12 मिनट की देरी से प्रारंभ करती है और परिणामस्वरूप उसे समय पर पहुंचने के लिए @45 किमी/घंटा के बजाय @54 किमी/घंटा की गति से गाड़ी चलानी पड़ी। तो यात्रा के दौरान तय की गयी दूरी ज्ञात कीजिए। 


Option “D” is correct.

Let, the distance covered = x km

According to the question,

⇒ x/45 – x/54 = 12/60

⇒ (6x – 5x)/270 = 1/5

⇒ x = 270/5 = 54

∴ Distance covered during the journey = 54 km

22. Sameer walks a certain distance and rides back taking a total time of 40 minutes. He could walk both ways in 60 minutes. How long would it take for him to ride both ways?

समीर एक निश्चित दूरी पैदल चलता है और गाड़ी से वापस आता है जिसमें वह 40 मिनट का कुल समय लेता है। वह दोनों तरफ से पैदल चलकर 60 मिनट में दूरी तय कर सकता है। तो गाड़ी से दोनों तरफ की दूरी तय करने में उसे कितना समय लगेगा?


Option “B” is correct.

Total time to travel and return to the same place by walking = 60 min

⇒ Total time to cover only one way by walking = 60/2

⇒ 30 min

Time to cover the distance by walking and riding back is 40 min

Total time to cover only one way by riding = 40 min – 30 min

⇒ 10 min

Total time to cover one way and returning back to the same place by riding = 10 × 2

⇒ 20 min.

∴ It will take 20 minutes for him to ride both ways.

23. A person covers the same distance at 3 km/h, 4 km/h, 7 km/h and 12 km/h and it takes a total of 340 minutes to cover this distance. What is the total distance (in km) covered by him?

एक व्यक्ति 3 किमी/घंटा, 4 किमी/घंटा, 7 किमी/घंटा और 12 किमी/घंटा की गति से समान दूरी को तय करता है और इस दूरी को तय करने में कुल 340 मिनट लगते हैं। तो उसके द्वारा तय की गयी कुल दूरी (किमी में) क्या है?


Option “C” is correct.

Distance is coverd in 4 equal parts

Let total distance be 4x

According to the question,

x/3 + x/4 + x/7 + x/12 = 34/6

⇒ (28x + 21x + 12x + 7x)/84 = 34/6

⇒ 68x = 476

⇒ x = 7

∴ Total distance = 4x = 28 km

24. A person travels from P to Q at a speed of 40 kmph and returns by increasing his speed by 50%. What is the average speed for both the trips?

एक व्यक्ति 40 किमी प्रति घंटे की गति से P से Q तक यात्रा करता है और अपनी गति को 50% बढ़ाकर वापस लौटता है। दोनों यात्राओं के लिए उसकी औसत गति क्या है?


Option “B” is correct.

Returning speed = 150 × 40 / 100 = 60 kmph

Average speed = 2x/ ((x/60) + (x/40)) = 2x/(x/24) = 2 × 24

 Average speed = 48 kmph

Shortcut Trick

Suppose a person covers a certain distance at x km/hr and an equal distance at y km/hr

Then the average speed during the whole journey is = 2xy/(x + y) km/hr.

25. A car covers a certain distance at a speed of 48 km/hr in 14 hours. How much time will it take to cover the same distance at the speed of 84 km/hr?

एक कार एक निश्चित दूरी 48 किमी/घंटे की गति से 14 घंटे में तय करती है। उसी दूरी को 84 किमी/घंटे की गति से तय करने में वह कितना समय लेगी?


Option “B” is correct.

Total distance covered by car in 14 hours with a speed of 48 km / hr = 48 × 14 km

Now the new speed = 84 km / hr

∴ Time taken by car = (48 × 14) / 84 = 8 hours

26. Arjun, traveling from Pune to Goa, covers a distance of 1000 km at 40 km/hr and the return journey at 60 km/hr. What was his average speed during his entire journey?

अर्जुन, पुणे से गोवा तक 1000 किमी की यात्रा में, 40 किमी/घंटे से दूरी तय करता है और 60 किमी/घंटे से वापसी यात्रा को तय करता है। उनकी पूरी यात्रा के दौरान उनकी औसत गति क्या थी?


Option “C” is correct.

Time taken by Arjun travelling from Pune to Goa = 1000/40 = 25 hr

Time taken by Arjun return from Goa to Pune = 1000/60 = 50/3 hrs

Total distance = 2 × 1000 = 2000

∴ Average speed = 2000/(25 + 50/3)

= (2000 × 3)/(75 + 50)

= 6000/125

= 48 km/hr

27.Sudhir travels 75 km at a speed of 15 kmph by cycle, 165 km at a speed of 33 kmph by bike, and 120 km at a speed of 15 kmph by horse cart. Find out the average speed of his entire distance traveled. 

सुधीर साइकिल से 15 किमी प्रति घंटे की गति से 75 किमी, बाइक से 33 किमी प्रति घंटे की गति से 165 किमी और घोड़ागाड़ी से 15 किमी प्रति घंटे की गति से 120 किमी की यात्रा करता है। उसकी पूरी यात्रा की औसत गति ज्ञात कीजिए।


Option “C” is correct.

⇒ Average speed (S) = Total distance/Total Time

⇒ S = (D1 + D2 + D3)/(T1 + T2 + T3)

⇒ T1 = 75/15 = 5 hr

⇒ T2 = 165/33 = 5 hr

⇒ T3 = 120/15 = 8 hr

⇒ S = (75 + 165 + 120)/(5 + 5 + 8)

⇒ S = 360/18

⇒ S = 20 kmph

∴ Hence, Average speed of entire travel is 20 kmph. 

28. A child goes around an equilateral triangular park. From A to B his speed is 10km/hr, from B to C his speed is 12 km/hr and from C to A his speed is 15 km/hr. Find his average speed.

एक बच्चा एक समबाहु त्रिभुजाकार पार्क के चारों ओर घूमता है। A से B तक उसकी गति 10किमी/घंटे है, B से C तक उसकी गति 12 किमी/घंटे है और C से A तक उसकी गति 15 किमी/घंटे है। उसकी औसत गति ज्ञात कीजिए।


Option “B” is correct.

Let the distance covered on each side be x km

As,

⇒ Speed = Distance/time

⇒ Time taken to cover side AC = x/10 hr

⇒ Time taken to cover side BC = x/12 hr

⇒ Time taken to cover side AC = x/15 hr

Now,

⇒ Avg. speed = (total distance/total time = (x + x + x)/{(x/10) + (x/12) + (x/15)} = 3x × {60/(6x + 5x + 4x)} = 180x/15x = 12 km/hr

29. A boy walks to his school from his village at 5 km/h and returns back at 7 km/h. If he takes 3 hours in all, then the distance between the village and the school is:

एक लड़का अपने गांव से अपने विद्यालय तक 5 किमी/घंटा की गति से चलता है और वापस 7 किमी/घंटा की गति से आता है। यदि वह कुल 3 घंटे लेता है, तो गांव और विद्यालय के बीच की दूरी क्या है?


Option “A” is correct.

Let the required distance be x km.

⇒ x/5 + x/7 = 3

Then,

⇒ (7x + 5x)/35 = 3

⇒ x = 8.75

30. A car travels for 6 hours at different speeds. For the first two hours at 60 m/s, for the next 2 hours at 50 m/s and for the remaining time at x m/s. If the average speed for the entire journey is 52 m/s, what is the value of x?

एक गाड़ी अलग-अलग गति से 6 घंटे तक यात्रा करती है। पहले दो घंटों के लिए 60 मीटर/सेकंड, अगले 2 घंटों के लिए 50 मीटर/सेकंड और शेष समय के लिए x मीटर/सेकंड पर यात्रा करती है। यदि सम्पूर्ण यात्रा के लिए औसत गति 52 मीटर/सेकंड है, तो x का मान क्या है?


Option “A” is correct.

Total distance = (60 + 50 + x)× 2 × 3600 m

As we know,

Average speed = Total distance/Total time

52 = [(60 + 50 + x)× 2 × 3600]/6 × 3600

110 + x = 52 × 3

x = 156 – 110

x = 46 m/sec