Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

31. Ramesh walked 6 km to reach the station from his house, then he boarded a train whose average speed was 60 km/h and thus he reached his destination. In this way he took a total time of 3 hours. If the average speed of the entire journey was 32 km/h then the average speed of walking is:

रमेश अपने घर से स्टेशन पर पहुँचने के लिए 6 किमी चलता है।फिर वह ट्रेन में चढ़ता है जिसकी औसत गति 60 किमी/घंटा है और फिर वह अपने गंतव्य स्थान पर पहुँचता है। इस संपूर्ण यातरा में उसे कुल 3 घंटे लगते हैं। यदि पूरी यात्रा की औसत गति 32 किमी/घंटा है तब उसके चलने की औसत गति कितनी थी? 

Option “D” is correct.

Total distance covered by Ramesh = 32 × 3

⇒ 96 km

Average speed of train = 60 km/hr

Let the time taken by train be x hrs

⇒ distance covered by train = 60 × x

Now, According to the question

6 + 60 × x = 32 ×  3

⇒ 6 + 60x = 96

⇒ 60x = 96 – 6

⇒ 60x = 90

⇒ x = 90/60

⇒ x = 1.5 hrs

Time taken by Ramesh to cover 6 km distance = 3 – 1.5 = 1.5 hrs

Walking speed of Ramesh = Distance/ time = 6/1.5 = 4 km/hr

∴ Average speed of walking is 4 km/hr

32. Pranav walked at 5 km/h for certain part of the journey and then he took an auto for the remaining part of the journey travelling at 25 km/h. if he took 10 hours for the entire journey, what part of journey did he travel by auto if the average speed of the entire journey be 17 km/h?

प्रणव अपनी यात्रा का कुछ भाग 5 किमी/घंटा की गति से चलता है और फिर वह ऑटो लेता है और अपनी यात्रा का शेष भाग 25 किमी/घंटा की गति से करता है। यदि वह संपूर्ण यात्रा में 10 घंटे का समय लेता है, तब उसने ऑटो द्वारा कितनी दूरी तय की होगी, यदि संपूर्ण यात्रा के दौरान औसत गति 17 किमी/घंटा है? 

Option “C” is correct.

   5               25

           17

    8      :        12

Ratio of time to cover the distance by walked to that of auto = 8: 12 or 2x : 3x

According to the question

(2x + 3x) = 10 hrs

⇒ 5x = 10 hrs

⇒ x = 10/5 = 2 hrs

⇒ 3x = 2 × 3 = 6 hrs

∴ Distance covered by auto in 6 hrs = 25 × 6 = 150 km

33. Prashant was going to Lucknow from Delhi by his car at an average speed of 60 kmph. After covering half of the distance he slows down his speed by 20 kmph. Then find his average speed during whole journey.

प्रशांत अपनी कार से 60 किमी/घंटा की औसत गति से दिल्ली से लखनऊ जा रहा था। आधी दूरी तय करने के बाद वह अपनी गति में 20 किमी/घंटा की कमी करता है। तो संपूर्ण यात्रा के दौरान उसकी औसत गति ज्ञात कीजिये।

Option “D” is correct.

Let distance between Aligarh and Lucknow be 120km

⇒ Time taken to travel half distance = 60/60 = 1 hrs

⇒ Time taken to travel remaining half distance = 60/40 = 1.5 hours

∴ Average speed = 120/(1 + 1.5) = 120/2.5 = 48 kmph

34. Sachin takes 20 minutes to run around the football ground one time, and 25 minutes to run around a second time. What is his average speed in miles per hour for the whole run if the football ground perimeter is 3 miles?

सचिन को एक बार फुटबॉल मैदान के चारों ओर दौड़ने में 20 मिनट लगते हैं, और दूसरी बार दौड़ने में 25 मिनट लगते हैं। अगर फुटबॉल ग्राउंड की परिधि 3 मील है तो पूरी दौड़ के लिए मील प्रति घंटे में उसकी औसत चाल क्या है?

Option “D” is correct.

Average speed = 6/ 0.75

Average speed = 8 miles/hour

35. A man covered 450 km at the rate of 75 km/hr and 360 km at the speed of 80 km/hr and remaining 195 km at 60 km/hr find the average speed of the whole journey.

एक आदमी ने 75 किमी/घंटा की दर से 450 किमी की दूरी और 80 किमी/घंटा की गति से 360 किमी और शेष 195 किमी 60 किमी/घंटा की गति से तय की, पूरी यात्रा की औसत गति ज्ञात कीजिये।

Option “D” is correct.

Time taken to cover 450 km = 450/75 hours

⇒ 6 hours

Time taken to cover 360 km = 360/80 hours

⇒ 9/2 hours

Time taken to cover 195 km = 195/60 hours

⇒ 13/4 hours

Now, Total time taken = [6 + (9/2) + (13/4)] hours

⇒ Total time taken = 55/4 hours

And, Total distance covered = (450 + 360 + 195) km

⇒ Total distance covered = 1005 km

And, Average speed = Total distance covered/Total time taken

⇒ Average speed = 1005 ÷ (55/4) km/hr

⇒ 804/11 km/hr

∴ The average speed of the whole journey is 804/11 km/hr

36. A person increases his speed by 10 km/h after traveling for every 20 km in a journey of a total length of 120 km. If the initial speed of the person is 10 km/h, then what will be the approximate (up to 2 decimal points) average speed of the person?

एक व्यक्ति 120 किमी की कुल यात्रा में हर 20 किमी की दुरी तय करने के बाद अपनी गति 10 किमी/घंटा बढ़ाता है। यदि व्यक्ति की प्रारंभिक गति 10 किमी/घंटा है, तो व्यक्ति की अनुमानित औसत गति (2 दशमलव अंकों तक) क्या होगी?

Option “B” is correct.

Initial speed = 10 km/h

Total time taken in the journey = [20/10] + [20/20] + [20/30] + [20/40] + [20/50] + [20/60]

= 2 + 1 + (2/3) + 0.5 + 0.4 + (1/3)

= 4.9 hours

∴ Average speed = 120/4.9 = 24.49 km/h (Approximately)

Thus, the correct answer is option 2.

37.A man covers 1/3 part of the journey in 24 minutes, the next 1/3 part of the journey in 20 minutes and the last 1/3 part of the journey in ‘t’ minutes. If the total distance covered by the man is 24 km and the average speed of man during the whole journey is 720/37 km/h, find the value of ‘t’.

एक आदमी अपनी यात्रा का 1/3 भाग 24 मिनट में तय करता है, यात्रा का अगला 1/3 भाग 20 मिनट में और अंतिम 1/3 भाग ‘t’ मिनट में तय करता है। यदि आदमी द्वारा तय की गयी कुल दूरी 24 किमी है और कुल यात्रा के दौरान आदमी की औसत गति 720/37 किमी/घंटा है, तो ‘t’ का मान ज्ञात कीजिये।

Option “D” is correct.

Time taken by man to cover the first part of the journey = 24 minutes = 24/60 hours

Time taken by man to cover the second part of the journey = 20 minutes = 20/60 hours

Time taken by man to cover the last part of the journey = ‘t’ minutes = t/60 hours

According to the question∶

24/[(24/60) + (20/60) + (t/60)] = 720/37

⇒ 24/[(44 + t)/60] = 720/37

⇒ 24 × 60/(44 + t) = 720/37

⇒ 2/(44 + t) = 1/37

⇒ t = 30 minutes

38. Pranav went to the bank at the speed of 60 km/h while returning for his home he covered the half of the distance at the speed of 10 km/h, but suddenly he realised that he was getting late so he increased the speed and reached the home by covering rest half of the distance at the speed of 30 km/h. The average speed of the Pranav in the whole length of journey is?

प्रणव 60 किमी/घंटा की गति से बैंक जाता है और अपने घर लौटते समय वह आधी दूरी को 10 किमी/घंटा की गति से तय करता है, लेकिन अचानक उसे महसूस होता है कि उसे देर हो रही है इसलिए वह अपनी गति बढ़ा लेता है और शेष आधी दूरी को 30 किमी/घंटा की गति से तय करता है और घर पहुँचता है। संपूर्ण यात्रा के दौरान प्रणव की औसत गति कितनी है?

Option “A” is correct.

Let the distance be 60 km.

⇒ Time taken by Pranav from home to bank = 60/60 = 1 hour

⇒ Time taken by Pranav to cover half distance between bank and home = 30/30 = 1 hour

⇒ Time taken by Pranav to cover half distance between bank and home = 30/10 = 3 hours

∴ Average Speed = (60 + 30 + 30) / (1 + 1 + 3) = 120/5 = 24 km/hr[/bg_collapse]

39. A car travels the first 39 kms in 45 minutes while the next 25 kms in 35 minutes. What is average speed of the car?

एक कार 45 मिनट में 39 किमी की दूरी तय करती है जबकि 25 किमी की दूरी 35 मिनट में तय करती है। कार की औसत गति क्या है?

Option “C” is correct.

Total Distance covered = 39 km + 25 km = 64 km

Total time taken = 45 min + 35 min = 80 min = (80/60) hours = 4/3 hours

Average Speed = 64/(4/3) km/hour

Average Speed = (64 × 3)/4 km/hour

Average Speed = (16 × 3) km/hour

∴ Average Speed = 48 km/hour 

40. A stenographer typed 16,200 words on a given day. If she had typed for exactly 6 hours during the day, then what will be her average speed of typing?

एक आशुलिपिक ने दिए गए एक दिन में 16,200 शब्द टाइप किए। यदि उसने दिन के दौरान ठीक 6 घंटे तक टाइप किया, तो उसकी टाइपिंग की औसत गति क्या होगी?

Option “C” is correct.

Time taken = 6 hours = 6 × 60 mins.

⇒ Time taken = 360 mins.

Average Speed = Total number of words/Time taken 

⇒ Average Speed = 16200/360

⇒ Average Speed = 45 words per minute

∴ The average speed of stenographer’s typing is 45 words per minute.