Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

41. A person covers a certain distance with 8 km/hr, he gets late by 12 minutes. If he covers the same distance with 12 km/hr, then he gets 2 minutes late only. Find the time in which he must reach the destination so that he is not late.

एक व्यक्ति एक निश्चित दूरी 8 किमी/घंटे की गति से तय करता है, उसे 12 मिनट की देरी हो जाती है। यदि वह समान दूरी को 12 किमी/घंटे से तय करता है तो उसे सिर्फ 2 मिनट की देरी होती है। वह समय ज्ञात कीजिए जिसमें वह गंतव्य तक बिना देरी के पहुँच जाए।

Option “A” is correct.

Suppose the distance to be covered = x km

∴ x/8 – 12/60 = x/12 – 2/60

⇒ x/8 – x/12 = 10/60

⇒ x = 4

∴ Scheduled time = 4/8 – 12/60 = 0.3 hours = 18 minutes

42. A man travels the same distance in a car at a speed 36 kmph and in a truck at a certain speed. If the same car of length 4.5 m moving in the same direction crosses the same truck of length 10.5 m in 3 seconds then, what will be the average speed of man in his journey of 216 km by the car and 360 km by the truck?

एक आदमी समान दूरी को एक कार द्वारा 36 किमी प्रति घंटे की गति से तय करता है और एक ट्रक द्वारा एक निश्चित गति से तय करता है। यदि 4.5 मी लंबाई की समान कार समान दिशा में चल रहे 10.5 मी लंबाई वाले समान ट्रक को 3 सेकंड में पार करती है, तो कार द्वारा 216 किमी की यात्रा और ट्रक द्वारा 360 किमी की यात्रा करने में आदमी की औसत गति कितनी होगी?

Option “C” is correct.

Given,

Speed of car = 36 kmph = 36 × 5/18 = 10 m/s

Length of car = 4.5 m

Length of truck = 10.5 m

Let the speed of truck be A m/s.

Relative speed = (10 – A)

Then,

⇒ 3 = (4.5 + 10.5)/(10 – A)

⇒ 30 – 3A = 15

⇒ A = 5 m/s

Speed of truck = 5 × 18/5 = 18 kmph

Total time taken by man = 216/36 + 360/18 = 26 hour

Total distance travelled = 216 + 360 = 576 km

Average speed = 576/26 = 22.15 kmph

43. A travels 15 km with a speed of 30 km/h. He travels another 25 km with a speed of 10 km/h. What is his average speed for the entire journey?

A 30 किमी/घंटा की गति के साथ 15 किमी की यात्रा करता है। वह 10 किमी/घंटा की गति के साथ 25 किमी की यात्रा और करता है। पूरी यात्रा के लिए उसकी औसत गति क्या है?

Option “A” is correct.

According to the question,

Total distance = 15 + 25 = 40 km

Total time = 15/30 + 25/10

⇒ (15 + 75)/30 = 90/30 = 3 hours

Average speed = 40/3 km/h

∴ The average speed for the entire journey is 40/3 km/h.

44. Bala travels first one-third of the total distance at the speed of 10 km/h and the next one-third distance at the speed of 20 km/h and the last one – third distance at the speed of 60 km/h. What is the average speed of Bala?

बाला कुल दूरी की पहली एक-तिहाई दूरी 10 किमी/घंटा की गति से और अगली एक-तिहाई दूरी 20 किमी/घंटा की गति से और अंतिम एक-तिहाई दूरी 60 किमी/घंटा की गति से तय करता है। बाला की औसत गति क्या है?

Option “A” is correct.

Let the total distance be 180 km.

⇒ 1/3rd of total distance = 180 × (1/3) = 60 km

Time taken by Bala to cover first one-third of the total distance = 60/10 = 6 hrs

Time taken by Bala to cover next one-third of the total distance = 60/20 = 3 hrs

Time taken by Bala to cover last one-third of the total distance = 60/60 = 1 hr

Average speed = Total time/total distance = 180/ (6 + 3 + 1) = 180/10 = 18 km/hr.

45. A train starts from place A to place B 20 km apart and reaches B in 2 hours. After that train starts from place B to place C 30 km apart and reaches destination C in 2 hours. Find the average speed of train in m/sec for the whole journey.

एक ट्रेन स्थान A से स्थान B के लिए प्रारंभ होती है, जो एक-दूसरे से 20 किमी की दूरी पर हैं और वह 2 घंटे में स्थान B पर पहुँचती है। उसके बाद ट्रेन स्थान B से स्थान C के लिए प्रारंभ होती है, जो एक-दूसरे से 30 किमी की दूरी पर है और वह 2 घंटे में गंतव्य C पर पहुँचती है। तो पूरी यात्रा के लिए मीटर/सेकेंड में ट्रेन की औसत गति ज्ञात कीजिए।

Option “C” is correct.

S1 = speed from A to B = 20/2 = 10 kmph

S2 = speed from B to C = 30/2 = 15 kmph

Average speed = (10 + 15)/2 = 25/2 kmph = 25/2 × 5/18 = 125/36 m/sec 

46. Neeraj covers two distances of 10 km and 20 km in 1 hour and 5 hours respectively. What will be the average speed of Neeraj for the whole journey?

नीरज 10 किमी और 20 किमी की दो दूरियां क्रमशः 1 घंटे और 5 घंटे में तय करता है। संपूर्ण यात्रा के लिए नीरज की औसत चाल क्या होगी?

Option “C” is correct.

Total distance = 10 + 20 = 30 km

Total time = 1 + 5 = 6 hours

∴ Average speed = 30/6 = 5 km/hour

47.A car travels 600 km in 9 hrs. and another 400 km in 11 hrs. The average speed of the car during the entire journey is – 

एक कार 9 घंटे में 600 किमी की यात्रा तय करती है और अन्य 400 किमी 11 घंटे में तय करती है। पूरी यात्रा के दौरान कार की औसत गति है –

Option “B” is correct.

Total Distance Covered = 600 + 400 = 1000 km

Total Time Taken = 9 + 11 = 20 Hours

Average speed = 1000/20 = 50 Km/h

∴ The Average Speed of the Car during entire journey is 50 km/h

48. If an athlete completes his race running at two different speeds of 15 km/hr. and 10 km/hr. in 30 seconds, find the total distance of the race.

यदि कोई एथलीट अपनी दौड़ को 30 सेकण्ड में 15 किमी/प्रतिघंटा और 10 किमी/प्रतिघंटा की दो अलग-अलग गति से पूरा करता है। तो दौड़ की कुल दूरी ज्ञात कीजिये।

Option “C” is correct.

When a body moves at two different speeds of ‘x’ km/hr. and ‘y’ km/hr., its average speed is computed as (2xy)/(x + y),

Average speed of athlete = (2 × 15 × 10)(15 + 10) = 300/25 = 12 km/hr = 12 × 5/18 = 10/3 m/sec

∵ Average speed = Total distance covered/Total time taken

∴ Total distance of race = 10/3 × 30 = 100 m

49. Ravi travelled from a place A to B at 40 km/h and from B to C at 60 km/h. If his average speed for the entire journey was 52 km/h, then AB : BC = ?

रवि A से B तक 40 किमी/घण्टे की गति से और B से C तक 60 किमी/ घंटे की गति यात्रा करता है। यदि पूरी यात्रा के लिए उसकी औसत गति 52 किमी/घंटा थी, तो AB : BC = ?

Option “D” is correct.

Let the distance between A and B be x km and the distance between B and C be y km.

According to question,

(x + y)/(x/40 + y/60) = 52

⇒ 120x + 120y = 52(3x + 2y)

⇒ 156x – 120x = 120y – 104y

⇒ 36x = 16y

⇒ x : y = 4 : 9

50. A’s average speed when he travels from home to office is 20% more than when he travels from office to home. He takes a break of 15 minutes for breakfast during his traveling. The distance between his home and office is 24 km. The total time taken by A in his whole journey is 45 minutes. Find the speed of A when he travels from office to home.

A जब घर से कार्यालय जाता है तब उसकी औसत गति कार्यालय से घर जाने की गति से 20% अधिक होती है। वह अपनी यात्रा के दौरान नाश्ते के लिए 15 मिनट का विराम लेता है। उसके घर और कार्यालय के मध्य की दूरी 24 किमी है। उनकी पूरी यात्रा में A द्वारा लिया गया समय 45 मिनट का है है। A की कार्यालय से घर जाने की गति ज्ञात कीजिये।

Option “A” is correct.

Let the speed of A when he travels from office to home be x.

Given that, Distance = 24 km

Total time taken by A in whole journey = 45 – 15 = 30 minutes = 1/2 hr

Now,

∴ 24/x + 24/1.2x = 30/60

⇒ x = 88 kmph

∴ A’s speed when he travels from office to home is 88 kmph.

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