Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

51. A person travels from P to Q at a speed of 50 km/h for 30 minutes. He then increases his speed to 60 km/h and reaches his destination R in 20 minutes. What is his average speed for the whole journey?

एक व्यक्ति 30 मिनट के लिए 50 किमी/घंटा की चाल से P से Q तक यात्रा करता है। फिर वह अपनी चाल को बढ़ाकर 60 किमी/घंटा कर लेता है और 20 मिनट में अपने गंतव्य R पर पहुंचता है। पूरी यात्रा के लिए उसकी औसत चाल क्या है?

Option “D” is correct.

As we know,

Average speed = Total distance/Total Time

Distance covered in 30 min with the speed of 50 km/hr = 50 × 1/2 = 25 km

Distance covered in 20 min with the speed of 60 km/hr = 60 × 1/3 = 20 km

Average speed = [(25 + 20)/(20 + 30)] × 60

Average speed = 45/50 × 60

Average speed = 54 km/hr

52. Suresh started his journey form P to Q by his bike at the speed of 40 km/h and then, the same distance he travelled on his foot at the speed of 10 km/h from Q to R. Then he returned from R to P via Q at the speed of 24 km/h. The average speed of the whole trip is:

सुरेश  P से Q तक अपनी यात्रा बाइक द्वारा 40 किमी/घंटा की  गति से तय करता है , फिर Q से R तक समान दूरी वह पैदल 10 किमी/घंटा की गति से चलता है। फिर वह Q से होते हुए R से P तक 24 किमी/घंटा की गति से वापस आता है। संपूर्ण यात्रा की औसत गति कितनी होगी? 

Option “D” is correct.

Let the distance between P and Q be 120 km. (LCM of 40, 10 and 24 = 120)

⇒ PQ = QR = 120 km

⇒ RP = 2 × 120 = 240 km

Time taken by Suresh from point P to Q = Distance/Speed = 120/40 = 3 hours

Time taken by Suresh from point Q to R = Distance/Speed = 120/10 = 12 hours

Time taken by Suresh from point R to P = Distance/Speed = 240/24 = 10 hours

∴ Average Speed = (120 + 120 + 240) / (3 + 12 + 10) = 480/25 = 19.2 km/hr

53. Two trains A & B covered a certain distance at a speed of 10km/hr and 15km/hr respectively then what is the average of the average speed and average of the speed of the trains?

दो ट्रेन A और B ने क्रमशः 10 किमी/घंटा और 15 किमी/घंटा की गति से एक निश्चित दूरी तय की, तो औसत गति और ट्रेनों की औसत गति का औसत क्या होगा?

Option “B” is correct.

Given:

Speed of train A (SA) = 10 km/hr

Speed of train B (SB) = 15 km/hr

Calculation:

Average speed of the trains = (2 × SA × SB)/(SA + SB)

⇒ (2 × 10 × 15)/(10 + 15)

⇒ 12 km/hr.

Average of the speed of the trains = (S+ SB)/2

⇒ (10 + 15)/2

⇒ 12.50 km/hr

Required average = (12 + 12.50)/2

⇒ 12.25 km/hr  

54. A car left 3 minutes early than the scheduled time and in order to reach the destination 126 km away in time, it has to slow its speed by 6 km/hr from the usual. What is the usual speed of the car?

एक कार अपने निर्धारित समय से 3 मिनट पहले चलना शुरू करती है और गंतव्य से 126 किमी. की दूरी पर इसे नियत समय पर अपनी यात्रा पूरी करने के लिए अपनी गति 6 किमी./घंटा कम करनी पड़ती है। कार की सामान्य गति क्या है?

Option “D” is correct.

Let usual speed of car be ‘x’ km/hr,

A car left 3 minutes early than the scheduled time and in order to reach the destination 126 km away in time, it has to slow its speed by 6 km/hr from the usual,

⇒ 126/ (x – 6) – 126/x = 3/60

⇒ 126 × [1/ (x – 6) – 1/x] = 3/60

⇒ x– 6x – 126 × 120 = 0

⇒ x– 126x + 120x – 126 × 120 = 0

⇒ x (x – 126) + 120(x – 120) = 0

⇒ x = 126

∴ Usual speed of car, x = 126 km/hr

55. The ratio between the speed of train and a car is 16 : 15 respectively. A bus covers a distance of 480 km in 8 hours. The speed of the Bus is three-fourth of the speed of the train, what is the distance covered by the car in 6 hours?

एक रेल और गाड़ी की गति के मध्य का अनुपात क्रमशः 16 : 15 है। एक बस 8 घंटे में 480 किमी की दूरी तय करती है। बस की गति रेल की गति से तीन-चौथाई है, 6 घंटे में गाड़ी द्वारा तय की गई दूरी क्या है?

Option “A” is correct.

Speed of the Bus = 480/8 = 60 km/hr

Speed of the Train = 60 × 4/3 = 80 km/hr

Speed of the Car = 80/16 × 15 = 75 km/hr

Distance covered by car = 75 × 6 = 450 km

56. The speed of train A is 25 km/h more than the speed of train B. A takes 4 hours less time to travel a distance of 300 km than what train B takes to travel 250 km. What is the speed (in km/h) of A?

रेल A की गति रेल B की गति से 25 किमी/घंटे अधिक है। A, 300 किमी की दूरी को तय करने में B द्वारा 250 किमी की दूरी को तय करने में लिए गये समय से 4 घंटे कम समय लेता है। A की गति (किमी/घंटे में) क्या है?

Option “A” is correct.

Go through options, check option A

Speed of A = 50 km/h and speed of B = 25 km/hr

⇒ 250/25 – 300/50 = 4

⇒ 10 – 6 = 4

⇒ 4 = 4 (Satisfies the given condition)

57.Walking 5/7 of his usual speed, a person reaches his office 10 minutes later than the usual time. His usual time in minutes is∶

अपनी सामान्य गति की 5/7 गुना गति से चलते हुए एक व्यक्ति अपने कार्यालय सामान्य समय से 10 मिनट की देरी से पहुँचता है। तो उसका सामान्य समय मिनटों में कितना है?

Option “B” is correct.

As we know,

Time is inversely proportional to speed.

Let usual speed of the person be 7x

Speed of the person after decreasing = 5x

Ratio of usual speed to after decreasing = 7x ∶ 5x

Ratio of usual time to after decreasing = 5x ∶ 7x

7x – 5x = 10

⇒ x = 5

∴ 5x = 5 × 5 = 25 min

58. A drives at the rate of 45 km/h and reaches its destination 4 minutes late. If speed is 60 km/h, A reaches 5 minutes early. The distance travelled by A is:

A, 45 किमी/घंटा की दर गाड़ी चलाता है और अपने गंतव्य पर 4 मिनट की देरी से पहुँचता है। यदि गति 60 किमी/घंटा है, तो A गंतव्य पर 5 मिनट पहले पहुँचता है। तो A द्वारा तय की गयी दूरी क्या है?

Option “C” is correct.

Let the current time to reach the destination b x hr, then

According to the question,

Distance is same, then

45 × (x + 4/60) = 60 × (x – 5/60)

⇒ 45x + 3 = 60x – 5

⇒ 60x – 45x = 5 + 3

⇒ 15x = 8

⇒ X = 8/15 hrs

Required Distance = 45 × (8/15 + 4/60) = 45 × 9/15 = 27 km

59. Given that the lengths of the paths of a ball thrown with different speeds by two boys are the same. If they take 0.6 seconds and 1 second respectively to cover the said length. What is the average speed of travel for the first throw if the same for the second is 96 km/hr?

दिया गया है कि दो लड़कों द्वारा अलग-अलग गति से फेंके गए एक गेंद के दूरियों की लम्बाई समान है। यदि वे उक्त लम्बाई को तय करने में क्रमशः 0.6 सेकंड और 1 सेकंड लेते हैं। पहले फेंक में यात्रा की औसत गति क्या है यदि दूसरे के लिए समान 96 किमी/घंटा है?

Option “A” is correct.

Ratio of time = 0.6 : 1 = 3 : 5

Length is equal

so, ratio of speed = 5 : 3

3 unit = 96

5 unit = 96 × 5/3 = 160 km/hr

60. A man travels a certain distance at 12 km/h and returns to the starting point at 9 km/h. The total time taken by him for the entire journey is 2(1/3) hours. The total distance (in km) covered by him is:

एक पुरुष 12 किमी/घंटा की गति से एक विशिष्ट दूरी तय करता है और 9 किमी/घंटा की गति से प्रारंभिक स्थान पर वापस आता है। पूरे यात्रा में उसके द्वारा लिया गया कुल समय 2(1/3) घंटा है। तो उसके द्वारा तय की गयी कुल दूरी (किमी में) क्या है?

Option “B” is correct.

Let the distance traveled be 2x.

Distance traveled in each directions = x 

Since, Time taken = Distance/Speed

According to the question,

⇒ x/12 + x/9 = 7/3

⇒ x = 12 km

∴ The total distance travelled by the man = 2 × 12 = 24 km (Forward and

backward)

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