Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

61. A train 360 km at a uniform speed. If the speed had been 10 km/h more, it would have taken 3 hours less for the same journey. What is the speed of the train (in km/h)?

एक ट्रेन 360 किमी दूरी एक समान गति से तय करती है। यदि गति 10 किमी/घंटा अधिक होती, तो उस यात्रा में 3 घंटे कम समय लगता। ट्रेन की गति (किमी/घंटा में) क्या है?

Option “C” is correct.

Let the original speed of the train be x km/h.

Time taken to cover a distance of 360 km = 360/x hours.

New speed of the train = (x + 10) km/h.

Time taken to cover a distance of 360 km at new speed = 360/(x + 10) hours.

Since, the train takes 3 hour less time,

∴ 360/x – 360/(x + 10) = 3

⇒ 360 (x + 10 – x)/x(x + 10) = 3

⇒ 120 × 10 = x2 + 10x

⇒ 1200 = x2 + 10x

⇒ x2 + 10x – 1200 = 0

⇒ x2 + 40x – 30x – 1200 = 0

⇒ x (x + 40) – 30( x + 40) = 0

⇒ (x + 40) (x – 30) = 0

⇒ x = (- 40), 30

But speed can not be in negative.

∴ x = 30 km/hr.

Hence, the original speed of the train is 30 km/h.

62. By travelling at 3/4th of his original speed Rahul reaches his office 12 minutes late than the usual time from his home, then what is the usual time taken by him to reach office?

राहुल अपने घर से अपनी प्रारंभिक गति की 3/4 वीं गति से यात्रा करके अपने कार्यालय सामान्य समय से 12 मिनट देरी से पहुंचता हैं, तो उसको कार्यालय पहुँचने में कितना सामान्य समय लगता है? 

Option “B” is correct.

Let the usual speed be 4x.

Changed speed = 3x

Distance between the office and home = D

According to the question:

(D/3x) – (D/4x) = (12/60)

D/12x = 0.2

(D/x) = 2.4

Usual time taken to reach office = (D/4x) = 2.4/4 = 0.6 hours = 36 minutes

63. A person takes 40 minutes more than his usual time when he covers a distance of 20 km at 5 km/h. If he covers the same distance at 8 km/h, he takes x minutes less than the usual time. What is the value of x?

एक व्यक्ति 20 किमी की दूरी 5 किमी/घंटा की गति से तय करने में अपने सामान्य समय से 40 मिनट अधिक लेता है। यदि वह यही दूरी 8 किमी/घंटा की गति से तय करता है, तब उसे सामान्य समय से x मिनट कम लगते हैं। x का मान क्या है?  

Option “A” is correct.

As we know,

Time = Distance/Speed = 20/5 = 4 hr

Usual time = 4 hr – 40 min = 3 hr and 20 min

Second condition

Speed of man = 8 km/hr

Time = Distance /Speed = 20/8 = 2 hr 30 min

Time difference = (3 hr + 20 min) – (2 hr + 30 min) = 50 min 

64. A motor car moves at a speed of 72 km/h and 54 km/h after and before repairing respectively. It covers X distance in 6 hours after repairing. How much time (in hours) will it take to cover 5X distance before repairing?

एक मोटर कार मरम्मत के बाद और मरम्मत से पहले क्रमशः 72 किमी/घंटा और 54 किमी/घंटा की गति से चलती है। यह मरम्मत के बाद X दूरी 6 घंटे में तय करती है। तो मरम्मत से पहले 5X दूरी तय करने के लिए यह कितना समय (घंटे में) लेगी?

Option “B” is correct.

Let T be the time taken by the car to cover 5X distance before repairing

Since, distance = speed × time

So, X = 72 × 6

⇒ X = 432 km

Now, according to question

5 × 432 = 54 × T

⇒ T = 40 hours

∴ Required time is 40 hours

65. A surveillance drone is moving between two points at the speed of 120 m/min and complete the one round in 10 min. After moving for 48 min, what distance more does the drone need to cover to reach another point? 

एक निगरानी ड्रोन दो बिंदुओं के बीच 120 मीटर/मिनट की गति से चल रहा है और 10 मिनट में एक चक्कर पूरा करता है। 48 मिनट तक चलने के बाद, अन्य बिंदु तक पहुंचने के लिए ड्रोन को कितनी दूरी तय करनी होगी?

Option “B” is correct.

Total distance covered in 10 min = 120 × 10 = 1200 m

One-side distance = 600 m

⇒ Four and a half rounds will be completed in 45 min

Distance covered in another 3 min = 120 × 3 = 360 m

Distance remaining to be covered to reach another point = 600 – 360 = 240 m

∴ After 48 min the distance needs to be covered 240 m to reach another point.

66. Amit travelled a distance of 50 km in 9 hours. He travelled partly on foot at 5 km/h and partly by bicycle at 10 km/h. The distance travelled on the bicycle is:

अमित ने 9 घंटे में 50 किमी की दूरी तय की। उन्होंने आंशिक रूप से 5 km/h की दर से पैदल यात्रा की और आंशिक रूप से 10 km/h की दर से साइकिल से यात्रा की। साइकिल पर तय की गई दूरी कितनी है?

Option “C” is correct.

Average speed = 50/9 km/hr

Using allegation method

10 km/hr 5 km/hr

50/9 km/hr

5/9 40/9

Time ratio to cover distance by bicycle to that of foot = 5/9 : 40/9 = 1 : 8

Now, (1 + 8) units = 9 hours

⇒ 1 unit = 1 hour

Hence, time taken by bicycle = 1 hour

Distance covered by bicycle = 10 × 1 = 10 km

67.Sheila can walk (16/17)th of her normal speed and takes 5 minutes more than the normal speed. Calculate the normal time it takes in determining a certain distance? (in minutes)

शीला अपनी सामान्य गति की (16/17) से चल सकती है और सामान्य गति की तुलना में 5 मिनट अधिक में एक निश्चित दूरी तय कर सकती है। उसके द्वारा एक निश्चित दूरी तय करने में लगने वाले सामान्य समय की गणना कीजिये? (मिनट में)

Option “C” is correct.

Let the speed of the Sheila be 17x

⇒ Speed of the Sheila after decrement = 17x × 16/17 = 16x

Speed ratio of normal speed to reduced speed = 17x : 16x

⇒ Time ratio of normal time to increased time = 16x : 17x

Extra time she will take due to reduced speed,17x – 16x = x

⇒ x = 5 min

Normal time taken by her, 16x = 5 × 16 = 80 min

∴ The total time taken by Sheila at normal speed was 80 min.

68. Anita goes to College at 20 km/h and reaches college 4 minutes late. Next time she goes at 25 km/h and reaches the college 2 minutes earlier than the scheduled time. What is the distance of her school?

अनीता 20 किमी/घंटा गति से कॉलेज जाती है और 4 मिनट की देरी से पहुँचती है। अगली बार वह 25 किमी/घंटा की गति से जाती है और निर्धारित समय से 2 मिनट पहले कॉलेज पहुँच जाती है। उसका कॉलेज कितनी दूरी पर है? 

Option “D” is correct.

When distance is constant

Time ∝ 1/Speed

Ratio of speed = 20 : 25

= 4 : 5

Ratio of time will we = 5 : 4

Let time be 5x and 4x

5x – 4x = ( 2 + 4) mins

⇒ x = 6 mins

5x = 30 mins

Distance = 20 × (30/60) = 10 km.

69. A man decides to travel 80 kilometers in 8 hours partly, by foot and partly on a bicycle. If his speed on foot is 8 km/hr and on bicycle 16 km/hr. what distance would he travel on foot?

एक आदमी 8 घंटे में 80 किलोमीटर की यात्रा पैदल और कुछ साइकिल से तय करता है। यदि पैदल उसकी गति 8 किमी / घंटा और साइकिल से 16 किमी / घंटा है। वह पैदल कितनी दूरी तय करेगा?

Option “C” is correct.

Let distance covered on foot be x km

⇒ Distance covered by bicycle = (80 – x) km

According to the question

x/8 + (80 – x)/16 = 8

⇒ (2x + 80 – x)/16 = 8

⇒ x + 80 = 128

⇒ x = 128 – 80

⇒ x = 48 km

∴ Distance covered by foot is 48 km.

70. Mohit starts moving from place A and reaches place B in 12 hours. He covers 1 / 5th part of the total distance at the speed of 6 km / hr and covers the remaining distance at the speed of 8 km / hr. What is the distance between A and B?

मोहित A स्थान से चलना शुरू करता है और B स्थान 12 घंटे में पहुंचता है। वह कुल दूरी का 1 / 5वां  हिस्सा  6 किमी/घंटे की गति से तय करता है और शेष दूरी को 8किमी/ घंटे की गति से तय करता है। A और B के बीच की दूरी क्या है?

Option “A” is correct.

Let the total distance be x

So according to question,

(x / 5) / 6 + (4x / 5) / 8 = 12

⇒ x / 30 + x / 10 = 12

⇒ 4x / 30 = 12

⇒ x = 90

∴ Distance between A and B = 90 km