Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

71. Suraj covers a distance of 18 km in 12 minutes. If his speed decreases by 30 km/hr, then how much time will Suraj take to cover the same distance?

सूरज 12 मिनट में 18 किमी की दूरी तय करता है। यदि उसकी गति 30 किमी/घंटा कम हो जाती है, तो सूरज को उसी दूरी को तय करने में कितना समय लगेगा?

Option “D” is correct.

Suraj covers a distance of 18 km in 12 minutes

⇒ Speed of Suraj = 18/12 = 1.5 km/min

His speed decreases by 30 km/hr

⇒ 30 km/hr = 30/60 = 0.5 km/min

On decreasing the speed, 

New speed = 1.5 – 0.5 = 1 km/min

Time = Distance/Speed

⇒ Time = 18/1 = 18 minutes

To cover the same distance after decreasing the speed by 30 km/hr, Suraj will take 18 minutes

72. A person covers a certain distance with a certain speed. If he increases his speed by 12.5% then he will be 10 min before. Find the initial time.

एक व्यक्ति एक निश्चित गति के साथ एक निश्चित दूरी तय करता है। यदि वह अपनी गति को 12.5% ​​बढ़ाता है तो वह 10 मिनट पहले पहुंच जाता है। प्रारंभिक समय का पता लगाएं।

Option “C” is correct.
Let the initial speed be 8x.
Final speed = 9x
Initial time = 9x
Final time = 8x
⇒ 9x – 8x = 10 min
⇒ x = 10 min
Initial time = 9 × 10
⇒ 90 min
∴ The initial time of the person is 90 min.

73. Distance between Surat and Delhi is 324 km. Two bikes start from Surat and Delhi towards each other at a same time and meet after 4 hours. Speed of one bike is 9 km/hr faster than other. Find the speed of slower bike.

सूरत और दिल्ली के बीच की दूरी 324 किमी है। दो बाइक एक ही समय पर सूरत और दिल्ली से एक दूसरे की ओर शुरू होती हैं और 4 घंटे के बाद मिलती हैं। एक बाइक की गति दुसरे की तुलना में 9 किमी / घंटा तेज है। धीमी बाइक की गति ज्ञात कीजिये।

Option “B” is correct.

Let the speed of slower bike be x km/hr.

Speed of faster bike = x + 9

Relative speed = 2x + 9

⇒ 2x + 9 = 324/4

⇒ 2x + 9 = 81

⇒ x = 36 km/hr

∴ The speed of slower bike be 36 km/hr.

74. If someone goes with 4/5th of his actual speed he reaches the distance 1.5 hours late. What was his actual time?

यदि कोई अपनी वास्तविक गति के 4/5 भाग से जाता है तो वह दूरी 1.5 घंटे देरी से पहुंचता है। उनका वास्तविक समय क्या था?

Option “A” is correct.

Let v, d, and t be the actual speed, distance, and time.

By using the above condition,

⇒ t = d/v       —-(1)

According to the question, when a person goes with (4/5)th of actual

speed, he is delayed by 1.5 hr.

⇒ (t + 3/2) = d/(4v/5) = 5d/4v

⇒ (t + 3/2) = 5t/4         {From equation (1)}

⇒ 5t/4 – t = 3/2

⇒ t/4 = 3/2

⇒ t = 6 hr

∴ Actual time of the person is 6 hr.

75. Walking at 7/9 of his usual speed, a person reaches his office 10 minutes later than the usual time. His usual time in minutes is: 

अपनी सामान्य गति की 7/9 गति से चलते हुए, एक व्यक्ति अपने कार्यालय में सामान्य समय से 10 मिनट बाद पहुंचता है। उसका सामान्य समय मिनटों में कितना है:

Option “C” is correct.

As we know,

Time is inversely proportional to speed.

Let the usual speed of the person be 9x

Speed of the person after decreasing = 7x

Ratio of usual speed to after decreasing = 9x : 7x

Ratio of usual time to after decreasing = 7x : 9x

9x – 7x = 10

⇒ x = 5

∴ 7x = 7 × 5 = 35 min

76. A starts walking at 4 kmph and after 4 hours, B starts cycling from the same point as that of A, in the same direction at 10 kmph. After how much distance from the starting point will B catch up with A (Correct to two decimal places)?

A, 4 किमी प्रति घंटे की गति से चलना शुरू करता है और 4 घंटों के बाद, B, A की तरह समान बिन्दु से उसी दिशा में 10 किमी प्रति घंटे की गति से साइकिल चलाना शुरू करता है। B प्रारम्भिक बिन्दु से कितनी दूरी के बाद, A तक पहुँच जाएगा (दशमलव के दो स्थानों तक)?

Option “D” is correct.

Speed of A = 4 km/h

Distance covered by A in 4 hours = 4 × 4 = 16 km

Speed of B = 10 km/h

Time taken by B to catch up with A = 16/(10 – 4) = 16/6 = 8/3 hr

Total distance covered by B in 8/3 hrs = 10 × 8/3 = 80/3 = 26.67 km

77.The ratio between the speeds of two trains is 2 ∶ 5. If the first train covers 350 km in 5 hours, then the speed (in km/h) of the second train is:

दो ट्रेनों की गतियों के बीच का अनुपात 2 ∶ 5 है। यदि पहली ट्रेन 5 घंटे में 350 किमी की दूरी तय करती है, तो दूसरी ट्रेन की गति (किमी/घंटा में) क्या है?

Option “C” is correct.

The ratio between the speeds of two trains = 2 ∶ 5

Speed of 1st train = 350/5 = 70 km/hr

Speed of 2nd train = 70 × 5/2 = 175 km/hr 

78. By increasing his speed by 15 km/h, a person reduced his travel time from 10 hours to 8 hours. How much time does he take to cover 375 km with his new speed?

एक व्यक्ति ने अपनी गति को 15 किमी/घंटे बढ़ाकर अपनी यात्रा का समय 10 घंटे से 8 घंटे तक कम कर लिया है। अपनी नई गति के साथ 375 किमी की दूरी तय करने में वह कितना समय लेता है?

Option “D” is correct.

Suppose his original speed = x km/h

∴ Speed after increase = (x + 15) km/h

According to problem,

⇒ x × 10 = (x + 15) × 8

⇒ 10x = 8x + 120

⇒ x = 60

∴ His new speed = (60 + 15) = 75 km/h

∴ Time required to cover 375 km = 375/75 = 5 hours

79. A train covers 60 km at a uniform speed. If the speed had been 8 km/h more, it would have taken 10 hours less for the same journey. What is the speed of the train (in km/h)?

एक ट्रेन एकसमान गति से 60 किमी की दूरी तय करती है। यदि गति 8 किमी/घंटा अधिक होती, तो समान दूरी को तय करने के लिए 10 घंटे कम लगते। तो ट्रेन की गति (किमी/घंटा में) क्या है?

Option “A” is correct.

Let the speed of train be x km /h

Distance = 60 km

So, time =  60 / x

When speed is 8 km/h more, time taken = 60/(x + 8)

According to the question,

60/x – 60/(x + 8) = 10

60 × (x + 8 – x)/x(x + 8)  =  10

60 ×  8 = x(x + 8)

48 = x2 + 8x 

x2 + 8x – 48 = 0

x2 + 12x – 4x – 48 = 0 

x(x + 12) – 4(x + 12) = 0

(x + 12)(x – 4) = 0

x = 4 or – 12

But x being speed cannot be negative.

So, x = 4

Hence, the speed of the train is 4 km/h.

80. The ratio between the speeds of two trains is 2 : 5. If the first train runs 250 km in 5 h, then the sum of the speeds (in km/ h) of both the trains is:

दो ट्रेनों की गति के बीच का अनुपात 2 : 5 है। यदि पहली ट्रेन 5 घंटे में 250 किमी चलती है, तो दोनों ट्रेनों की गति का योग (किमी/घंटा में) ज्ञात कीजिए।

Option “C” is correct.

Let the speed of two trains be 2x and 3x

Speed of first train = 250/5 = 50 km/h

∴ 2x = 50

⇒ x = 25 km/h

∴ The sum of the speeds of both train = 2x + 5x = 7x = 7 × 25 = 175 km/h