Top 130 Most Asked Speed Distance Time Questions [ 100% FREE ]

Understanding the concepts of speed, distance, and time is not just for the curious minds; it’s essential for a variety of real-world applications and competitive exams. And when it comes to cracking these exams, practicing the right set of Speed Distance Time questions is crucial.

Why, you ask? Because Speed Distance Time questions frequently pop up in examinations, and being well-versed with them can give you a notable edge. This article is a treasure trove for those who are looking for the most asked Speed Distance Time questions.

Questions related to the time and distance formula are a staple in both school and competitive exams. This formula finds its use in diverse topics like motion in a straight line, races, and even clocks. So, what is the relation between speed, distance, and time?

Well, in simple terms, distance traveled is the product of speed and the time for which an object has been in motion. We dive deeper into these concepts, answering some of the most frequently asked time speed and distance questions. Additionally, we’ve compiled some popular speed time and distance questions, as well as speed time and distance questions with answers in a PDF format, ensuring that you’re not just practicing but also checking your answers.

For those keen on aptitude, our collection includes time speed and distance aptitude problems. We’ve also incorporated speed time and distance problems with solutions to assist you in understanding where you might have gone wrong and to learn the right approach.

To give you a sneak peek, the time and distance formula revolves around the equation:

Distance (d) = Speed (v) × Time (t). This formula and its variants are the backbone of numerous speed time and distance questions. If you wish to explore the intricacies of the time and distance formula in detail, you can find more information here.

In conclusion, whether you’re preparing for an upcoming exam or just wish to brush up your knowledge, this comprehensive article promises a deeper insight into speed, time, and distance concepts. So gear up and dive into our meticulously curated list of Speed Distance Time questions. Happy learning!

81. The distance between Kanpur and Allahabad is 200 km, a bus started from Kanpur towards Allahabad with speed 20% less than its original speed. After travelling to a certain distance, it increases its speed by 60% from its original speed in order to reach Allahabad on time. For how long the bus travelled with increased speed?

कानपुर और इलाहाबाद के बीच की दूरी 200 किमी है। कानपुर से इलाहाबाद की ओर जाने वाली एक बस अपनी मूल गति से 20% कम गति के साथ शुरू हुई और निश्चित दूरी तक यात्रा करने के बाद समय पर इलाहाबाद पहुँचने के लिए अपनी गति को अपनी मूल गति से 60% तक बढ़ा देती है। कितनी दूरी के लिए बस बढ़ी हुई गति से चली?

Option “D” is correct.

Let the original speed of the bus be 100x.

Decreased speed = 80% of 100x = 80x

After increase, speed = 160% of 100x = 160x

Let the bus travelled for ‘D’ km with increased speed.

According to the question:

[(200 – D)/80x] + [D/160x] = 200/100x

⇒ (200 – D) + D = 2 × 160

⇒ 400 – 2D + D = 320

⇒ D = 80

Hence, for 80 km, the bus travelled with increased speed.

82. Two people A and B are initially 8 km apart and they start traveling towards each other at the same time. They meet after travelling for 30 minutes and the time taken by B to reach A is 32 minutes more than the time taken by A to reach B, then what is the speed of A?

दो व्यक्ति A और B आरम्भ में  8 किमी की दूरी पर थे और फिर उन्होंने एक ही समय पर एक दूसरे की ओर चलना शुरू किया। वे 30 मिनट की यात्रा करने के बाद एक दूरे से मिले और B को A तक पहुँचने में, A की तुलना में B तक पहुँचने में लगने वाले समय से 32 मिनट अधिक लगते हैं। अब, A की गति क्या है ?

Option “C” is correct.

Let speed of A and B be a and b respectively. (a > b; as B takes more time that A to cover same distance.)

According to the question:

8/(a + b) = (30/60)

⇒ (a + b) = 16

⇒ a = (16 – b)     —-(1)

Again, according to the question

(8/a) + (32/60) = (8/b)

From equation (1), we have 

[8/(16 – b)] + (8/15) = (8/b)

⇒ (8/b) – [8/ (16 – b)] = 8/15

⇒ 15[8(16 – b) – 8b] = 8b(16 – b)

⇒ 15(16 – b – b) = b(16 – b)

⇒ 240 – 30b = 16b – b2

⇒ b2 – 46b + 240 = 0

⇒ b = 6 and 40

a = 10 and -24 (Not valid)

Hence, speed of A = 10 km/h

83. A man covered a distance of 2000 km in 18 hours partly by bus at 72 kmph and partly by train at 160 kmph. The distance covered by bus is

एक आदमी ने 2000 किमी की दूरी 18 घंटे में तय की, उसने कुछ दूरी बस द्वारा 72 किमी प्रति घंटे की गति से और कुछ दूरी ट्रेन द्वारा 160 किमी प्रति घंटे की गति से तय की। बस द्वारा तय की गई दूरी क्या है?

Option “B” is correct.

Let the distance covered by bus be x km, then

Distance covered by train be (2000 – x) km.

According to the question,

x/72 + (2000 – x)/160 = 18

[20x + 9 (2000 – x)]/1440 = 18

20x + 18000 – 9x = 18 × 1440

11x = 25920 – 18000 = 7920

x = 7920/11

x = 720 km

84. A man is walking at a speed of 12 km per hour. After every kilometre, he takes rest for 4 minutes. How much time (in minutes) will he take to cover a distance of 8 kilometres?

एक आदमी 12 किमी प्रति घंटे की गति से चल रहा है। प्रत्येक किलोमीटर के बाद, वह 4 मिनट के लिए विश्राम करता है। 8 किलोमीटर की दूरी को तय करने में उसे कितना समय (मिनट में) लगेगा?

Option “A” is correct.

Since the speed of man is 12 km per hour

⇒ 12 km distance can be covered by the man in 1 hour (60 minutes)

⇒ 1 km distance can be covered by the man in 60/12 minutes = 5 minutes

And he takes a rest for 4 minutes after every kilometre

⇒ He takes (5 + 4) minutes to cover 1 km

⇒ He will take (7 × 9) minutes to cover 7 km

∴ Total time to cover 8 km by the man will be (63 + 5) = 68 minutes 

85. Two racers run at a speed of 100 m/min and 120 m/min, respectively. If the second racer takes 10 minutes less than the first to complete the run, then how long is the race?

दो धावक क्रमशः 100 मीटर/मिनट और 120 मीटर/मिनट की गति पर दौड़ते हैं। यदि दूसरा धावक दौड़ को पूरा करने के लिए पहले धावक से 10 मिनट कम लेता है, तो दौड़ कितनी लंबी है?

Option “A” is correct.

Speed ratio of two racers = 100 : 120 = 5x : 6x

As we know,

Time is inversely proportional to speed.

Time ratio of two racers = 6x : 5x

⇒ 6x – 5x = 10 min

⇒ x = 10 min

Time taken by first racer to complete race = 6 × 10 = 60 min

Distance = Speed × Time

∴ Distance = 60 × 100 = 6 km

86. Two cars A and B leave from Delhi at 8:30 a.m. and at 9 a.m. to Shimla, respectively. They travel at speeds of 40km/h and 50 km/h respectively. How many kilometres away from Delhi will the two cars be together?

दो गाड़ियाँ A और B दिल्ली से शिमला के लिए क्रमशः प्रातः 8:30 बजे और प्रातः 9:00 बजे निकलती हैं। वे क्रमशः 40 किमी/घंटे और 50 किमी/घंटे की गति से चलती हैं। दिल्ली से कितने किमी की दूरी पर दोनों गाड़ियाँ एक साथ होंगी?

Option “D” is correct.

Speed of first cars = 40 km/hr

Speed of second cars = 50 km/hr

Relative speed, if same direction = 50 – 40 = 10 km/hr

Distance cover by first cars in 1/2 hr = 40 × 1/2 = 20 km

Time = distance/speed

Both cars be together in = 20/10 = 2 hr

Distance cover by second car in next 2 hr to meet first car = 50 × 2 = 100 km

87.A man by cycling goes from hostel to college at 15 km/hr and gets late by 2 minutes. He runs the bike at 20 km/hr, it will arrive 2 minutes early. Find the distance between hostel and college distance. (In KM)

एक आदमी हॉस्टल से कॉलेज तक 15 किमी/घंटा की गति से साइकल चलाते हुए दूरी तय करता है और 2 मिनट देरी से पहुंचता है। वह 20 किमी/घंटा की गति से बाइक चलाता है, तो वह 2 मिनट पहले पहुँच जाता है। हॉस्टल और कॉलेज के बीच की दूरी ज्ञात कीजिये। (किमी में)

Option “A” is correct.

Let distance be x.

According to question

x/15 – x/20 = 4/60

⇒ (4x – 3x)/60 = 4/60

⇒ x/60 = 4/60

⇒ x = 4 km

88. Anita walks away from her usual 9/10 speed and takes 21 minutes more than usual. Find the normal time taken. (in minutes)

अनीता अपनी सामान्य गति के 9/10 गति से चलती है और सामान्य से 21 मिनट अधिक लेती है। लिया गया सामान्य समय ज्ञात कीजिए। ( मिनट में)

Option “A” is correct.

Let the speed of the Anita be 10x

⇒ Speed of the Anita after decrement = 10x × 9/10 = 9x

Speed ratio = 10x : 9x

⇒ Time ratio = 9x : 10x

10x – 9x = x

⇒ x = 21 min

⇒ 9x = 9 × 21 = 189 min

∴ Total time taken by Anita in the starting was 189 min.

89. A person driving at a speed of 42 km/h reaches office 1 minute early, whereas if driving at a speed of 36 km/h, the person reaches office 3 minutes late. What is the distance (in km) that the person is covering?

एक व्यक्ति 42 किमी/घंटे की गति से चलते हुए अपने कार्यालय 1 मिनट पहले पहुंचता है, जबकि यदि वह 36 किमी/घंटे की गति से चलता है तो कार्यालय 3 मिनट देर से पहुंचता है। उस व्यक्ति द्वारा तय की जा रही दूरी (किमी में) क्या है?

Option “B” is correct.

According to the question,

⇒ (x/36) – (x/42) = 4/60 = 2/30

LCM of 36, 42, 30 is 1260

⇒ 35x – 30x = 84

⇒ 5x = 84

⇒ x = 84/5 = 16.8 km

∴ Distance the person is covering is 16.8 km

90. Piyush is running at the speed of 8 km/hour and he stops for 5 minutes to take rest at the end of every third km. What will be the time taken by Piyush to cover a distance of 56 km?

पीयूष 8 किमी / घंटे की गति से चल रहा है और वह हर तीसरे किलोमीटर के अंत में आराम करने के लिए 5 मिनट के लिए रुकता है। पीयूष को 56 किमी की दूरी तय करने में कितना समय लगेगा?

Option “D” is correct.

In 56 km he will stop for times = 56/3 = 18.67

That means he will stop for 18 times

Total rest time = 18 × 5 = 90 min = 1 hour 30 min

And time taken to complete journey without rest = 56/8 = 7 hours

∴ Time taken by Piyush to complete the journey = 7 + (1 hour + 30 min) = 8 hour 30 min

Pages: 1 2 3 4 5 6 7 8 9 10 11 12 13