Master Percentage Questions for Competitive Exams [100% Free and Effective!]

Percentage Questions : When it comes to preparing for competitive examinations, “percentage questions” stand out as a crucial topic every aspirant must grasp. Whether you’re gearing up for the Bank, SSC, Railways, or other government exams, “percentage questions” consistently feature as a key component of the syllabus. This comes as no surprise since understanding “percentage questions” lays the foundation for various other mathematical concepts.

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If you delve into past papers and mock tests, you’ll frequently encounter “percentage questions for competitive exams”. And, it doesn’t stop there. The variations of “questions on percentage for competitive exams” are manifold, each presenting its unique challenge. Moreover, “percentage competitive questions” are known to have tricked even the most seasoned of candidates, emphasizing their importance.

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By the end, our goal is for you to look at “percentage questions” not as a challenge but as an opportunity, an opportunity to score and excel in the Bank, SSC, Railways, and other government exams. So, let’s embark on this percentage-filled journey together!

141. A spends 40% of his salary for education fee, 20% of the salary for shopping and remaining for house rent. If the difference between the amounts spend for house rent and shopping is Rs.4000, then find the salary of A?

A अपने वेतन का 40% शिक्षा शुल्क, शॉपिंग के लिए वेतन का 20% और शेष घर के किराए के लिए खर्च करता है। यदि मकान किराए और खरीदारी के लिए खर्च की गई राशि के बीच का अंतर 4000 रूपये है, तो A का वेतन ज्ञात कीजिए?

Option “C” is correct.

Salary = x

Education fee = 40/100 * x

Shopping = 20/100 * x

House rent = 40x/100

 Difference = 40x/200 – 20x/100 = 4000

20x = 400000

x = Rs.20000

142. Ram scored 20% marks more than Rakesh and Rakesh scored 25% marks less than Ritesh in an exam having 200 as maximum marks. If Ritesh’s marks is 16 more than that of Ram. What is the percentage marks obtained by Rakesh?

अधिकतम 200 अंकों की एक परीक्षा में, राम ने राकेश से 20% अधिक अंक हासिल किया और राकेश ने रितेश से 25% कम अंक हासिल किया। यदि रितेश के अंक राम के अंक से 16 अधिक हैं, राकेश ने कितने प्रतिशत अंक प्राप्त किए?

Option “D” is correct.

Let the marks obtained by Ritesh is 4x

Marks obtained by Rakesh = 75/100 * 4x = 3x

Marks obtained by Ram = 120/100 * 3x = 18/5x = 3.6x

ATQ,

4x – 3.6x = 16

0.4x = 16

x = 40

Rakesh score = 40 * 3 = 120

Percentage = 120/200 * 100 = 60%

143. During dieting, the weight of Suku in every month was decreased by 10% compared with its previous month. In April he started dieting and in July of the same year his weight was 87.48 kg. What was his weight, when he started dieting?

डाइटिंग के दौरान, हर महीने सुकु का वजन पिछले महीने के मुकाबले 10% कम हो गया था अप्रैल में उन्होंने डाइटिंग शुरू की और उसी साल जुलाई में उनका वजन 87.48 किलोग्राम था। जब उन्होंने डाइटिंग शुरू की तो उनका वजन कितना था?

Option “A” is correct.

In April, let his weight = a kg

In May, his weight = 90% of a = 0.9a kg

In June, his weight = 90% of 0.9a = 0.81a kg

In July, his weight = 90% of 0.81a = 0.729a = 87.48 kg

a = 87.48/0.729 = 120 kg

Or

In April his weight = 87.48 * 100/90 * 100/90 * 100/90 = 120 kg

144. In an examination, it is required to get 750 aggregate marks to pass. A student gets 606 marks and he is declared failed by 12 % of the total marks. What is the maximum aggregate mark of the exam?

एक परीक्षा में, पास होने के लिए 750 एग्रीगेट अंक लाना आवश्यक है। एक छात्र को 606 अंक प्राप्त होते हैं और उसे कुल अंकों में 12% से फेल घोषित किया जाता है। एक छात्र को अधिकतम कितने एग्रीगेट अंक मिल सकते हैं?

Option “C” is correct.

Let the maximum aggregate marks be x,

(12/100)*x = 750 – 606

(12/100)*x = 144

x = 144*(100/12) = 1200

Maximum aggregate marks = 1200

145. The number of male population in Syria is 6 lakhs. If the number of male and female population in Syria is increased by 15% and 25% respectively, then now the female population is 31000 more than the male population. Find the initial female population in Syria

सीरिया में पुरुष आबादी की संख्या 6 लाख है। यदि सीरिया में पुरुष और महिला आबादी की संख्या में क्रमशः 15% और 25% की वृद्धि की जाती है, तो अब महिला आबादी पुरुष आबादी से 31000 अधिक है। सीरिया में प्रारंभिक महिला आबादी ज्ञात करें?

Option “C” is correct.

Number of female population = x

(x * 125/100) – (600000 * 115/100) = 31000

x = 576800

146. In a population 20% of women are 200 less than three fifth of the total women population .Then how many number of women are there?

एक आबादी में 20% महिलाएं, कुल महिला आबादी के 3/5वें हिस्से से 200 कम है। फिर महिलाओं की संख्या कितनी है?

Option “D” is correct.

Let the population of the women be x.

Then (3/5) x – ( 20% of x ) = 200

        3 x/5  – ( 20 x / 100 ) = 200

                                  x     = 500

147. The population growth of Chennai increases every year by 10% and the number of population in 2018 is 89540, what is the population in Chennai in 2016?

चेन्नई की जनसंख्या हर साल 10% बढ़ जाती है और 2018 में जनसंख्या की संख्या 89540 है, 2016 में चेन्नई की जनसंख्या क्या थी?

Option “A” is correct.

Population in 2016 = x

x * 110/100 * 110/100 = 89540

x = 74000

148. The population of a city increases by 15% per year. If its current population is 12 lakhs, then what will be the population after three years?

एक शहर की जनसंख्या में प्रति वर्ष 15% की वृद्धि होती है। यदि इसकी वर्तमान जनसंख्या 12 लाख है, तो तीन वर्ष बाद जनसंख्या क्या होगी?

Option “B” is correct.

Population after 3 years

= > 1200000*(115/100)*(115/100)*(115/100)

= > 1825050

149. The population of a town decreases at the rate of 10% first year and it increases at the rate of 10% second year and so on. If the present population of the town is 356400, find the population of the town 3 years ago.

एक नगर की जनसंख्या पहले वर्ष 10% की दर से घटती है और दूसरे वर्ष 10% की दर से बढ़ती है। यदि नगर की वर्तमान जनसंख्या 356400 है, तो 3 वर्ष पहले नगर की जनसंख्या ज्ञात कीजिए।

Option “D” is correct.

The required population

 = (356400 x 100 x 100 x 100)/((100 – 10) x (100 + 10) x (100 – 10))

= (356400 x 100 x 100 x 100)/(90 x 110 x 90)

= 400000 = 4 lakh

150. The population of a city decreases every year by 10%. If the population of the city after three years becomes 6561, then find the present population of the city.

एक शहर की जनसंख्या में प्रतिवर्ष 10% की कमी होती है। यदि तीन वर्ष बाद शहर की जनसंख्या 6561 हो जाती है, तो शहर की वर्तमान जनसंख्या ज्ञात कीजिए।

Option “C” is correct.

Let the present population of the city = x

x * (100 – 10)/100 * (100 – 10)/100 * (100 – 10)/100 = 6561

x * 90/100 * 90/100 * 90/100 = 6561

x = 9000

The present population of the city = 9000