Master Percentage Questions for Competitive Exams [100% Free and Effective!]

Percentage Questions : When it comes to preparing for competitive examinations, “percentage questions” stand out as a crucial topic every aspirant must grasp. Whether you’re gearing up for the Bank, SSC, Railways, or other government exams, “percentage questions” consistently feature as a key component of the syllabus. This comes as no surprise since understanding “percentage questions” lays the foundation for various other mathematical concepts.

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261. While measuring the sides of a square box, Raghu mistakenly added 4% extra. What is the error percentage in the calculated area of square?

एक वर्गाकार बॉक्स के भुजाओं को मापने के दौरान, रघु ने गलती से 4% अतिरिक्त जोड़ दिया। गणना किये गए वर्ग के क्षेत्रफल में त्रुटि प्रतिशत क्या है?

A. 8.16%
B. 10%
C. 12%
D. 11%
E. 13%

Option “A” is correct.

Let the side of the square = 100cm. mistakenly measured = 104cm

Error % = Error value/True value * 100

= [1042 – 1002]/1002 * 100

= (104 + 100)(104 – 100)/100

= 8.16%

262. By what percentage of the breadth of the parallelogram is decreased if the length of the parallelogram is increased by 20% and the area is to be kept same?

यदि समानांतर चतुर्भुज की लंबाई में 20% से वृध्दि की गई है और क्षेत्रफल को समान रखा जाना है, तो समांतर चतुर्भुज की चौड़ाई में कितने प्रतिशत से कमी की गई है?

A. 16(2/3)%
B. 9(1/9)%
C. 18(1/3)%
D. 20%
E. None of these

Option “A” is correct.

Let Initial length and breadth of parallelogram 100 cm and 100 cm respectively.

New breadth of parallelogram = x

100 * 100 = 120 * x

x = 500/6

Decreased by = 100 – 500/6 = 100/6

Required percentage = 100/6%

= 16(2/3)%

263. If each side of a cube is increased by 30 %, then find by how much percentage the volume of the cube be increased?

यदि एक घन की प्रत्येक भुजा में 30% की वृद्धि की जाती है, तो ज्ञात कीजिए कि घन के आयतन में कितने प्रतिशत की वृद्धि हुई है?

A. 119.7 %
B. 121.5 %
C. 134.8 %
D. 108.2 %
E. None of these

Option “A” is correct.

Let the side of a cube be a

Volume of a cube = a3

Side of the new cube = a * (130/100) = 1.3 a

Volume of new cube = (1.3 a)3 = 2.197 a3

Increase % = [(1.197 a3)/a3] * 100 = 119.7 %

264. The ratio of a, b and c is 4: 2: 1 and the sum of squares of a, b and c is 84. What is the value of 50% of sum of a, b and c?

a, b और c का अनुपात 4: 2: 1 है और a, b और c के वर्गों का योग 84 है। a, b और c के योग के 50% का मान क्या है?

A. 5
B. 7
C. 8
D. 10
E. None of these

Option “B” is correct.

a = 4x, b = 2x and c = x

16x2 + 4x2 + x2 = 84

=> x = 2

a + b + c = 4x + 2x + x = 7x = 14

50% of (a + b + c) = 7

265. If the length of the cuboid increased by 30%, height of the cuboid is increased by 10% and the breadth of the cuboid is decreased by 40%. Then find the volume will be increased or decreased by.

यदि घनाभ की लंबाई 30% बढ़ जाती है, तो घनाभ की ऊंचाई 10% बढ़ जाती है और घनाभ की चौड़ाई 40% तक कम हो जाती है। तब बढ़ाया या घटाया गया आयतन ज्ञात कीजिये।

A. 14.2% increased
B. 12.5% decreased
C. 8.2% increased
D. 13.6% decreased
E. None of these

Option “E” is correct.

Let the initial volume=100

Volume increased or decreased by=100*130/100*110/100*60/100

=85.8%

=14.2% decreased

266. A conical vessel covers a base area of 154 cm2. If the height of the vessel is 45% more than the radius of its base, find its volume approximately.

एक शंक्वाकार बर्तन का आधार क्षेत्रफल 154 वर्ग सेमी है। यदि बर्तन की ऊंचाई इसके आधार के त्रिज्या से 45% अधिक है, तो इसकी आयतन लगभग ज्ञात करें।

A. 450cm3
B. 500cm3
C. 521cm3
D. 678cm3
E. None of these

Option “C” is correct.

∏ * r2 = 154 => r = 7cm

Required volume = 1/3 * ∏ * r2 * h

= 1/3 * 22/7 * 7 * 7 * (145% of 7)

= 521.03 = 521 cm3

267. A rectangle diagram is drawn in a paper. If each side of the rectangle is increased by 10%, what is the percentage increase in its area?

एक आयत आरेख एक कागज में खींचा गया है। यदि आयत के प्रत्येक भुजा में 10% की वृद्धि की जाती है, तो उसके क्षेत्रफल में प्रतिशत वृद्धि क्या है?

A. 21%
B. 24%
C. 28%
D. 38%
E. None of these

Option “A” is correct.

Length = x meter and Breadth = y meter

Original area = xy meter2

New area = (110/100)2 * xy = 121/100 * xy meter2

% increase = [(121xy/100) – xy]/xy * 100

= 21%

268. Area of a square is 576 cm². A rectangle has length 37.5% more than side of given square and breadth is 25% less than side of the square. Find the area of rectangle is how much % more or less than area of square?

एक वर्ग का क्षेत्रफल 576 सेमी² है। एक आयत की लंबाई, दिए गए वर्ग की भुजा की तुलना में 37.5% अधिक है और चौड़ाई, वर्ग की भुजा की तुलना में 25% कम है। ज्ञात कीजिए कि आयत का क्षेत्रफल, वर्ग के क्षेत्रफल से कितने% अधिक या कम है?

A. 3.250% less
B. 3.375% more
C. 3.500% less
D. 3.125% more
E. None of these

Option “D” is correct.

Side of square = √576 = 24 cm

Length of rectangle = 137.5% of 24 = 11/8 x 24 = 33 cm

Breadth of rectangle = 75% of 24 = 3/4 x 24 = 18 cm

Area of rectangle = 33 x 18 = 594 cm2

Required % change = (594 – 576)/576 x 100 = 3.125% more

269. The breadth of the rectangle is 40% of its length. If the length of the rectangle is decreased by 50%, then the area of the rectangle is increased by 25%. Find the percentage Changes of breadth of the rectangle?

आयत की चौड़ाई उसकी लंबाई का 40% है। यदि आयत की लंबाई में 50% की कमी की जाती है, तो आयत के क्षेत्रफल में 25% की वृद्धि होती है। आयत की चौड़ाई में प्रतिशत वृद्धि ज्ञात कीजिए?

A. 120%
B. 250%
C. 180%
D. 200%
E. 150%

Option “E” is correct.

Length of rectangle = 100x

Breadth = 100x * 40/100 = 40x

Area of the rectangle = 100x * 40x

New length of rectangle = 100x * 50/100 = 50x

New area of the rectangle = 100x * 40x * 125/100 = 5000x2

New breadth = 5000x2/50x = 100x

Required % = (100x – 40x)/40x * 100

= 150%

270. The radius and the height of a right circular cylinder are increased by 30% and 20% respectively. What will be the percentage increase in curved surface area?

त्रिज्या और एक लंब वृत्तीय बेलन की ऊंचाई क्रमशः 30% और 20% बढ़ जाती है। घुमावदार क्षेत्र में प्रतिशत वृद्धि क्या होगी?

A. 60%
B. 56%
C. 75%
D. 52%
E. none of these

Option “B” is correct.

Let the radius = 100 and height = 100

= > old area : new area = 2*π*100*100: 2*π*130*120

= > old area : new area = 25 : 39

Required % = 14*100/25 = 56%